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Svetradugi [14.3K]
3 years ago
10

an antelope can run at a speed of 61 miles per hour. What is this speed in yards per second? Round to the nearest hundredth.

Mathematics
1 answer:
arlik [135]3 years ago
5 0
20.3 yards per second.
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What is the distance from M(9,-4) to NC-1, -2)?
Ilia_Sergeevich [38]

Answer:

Exact Form: 2√26

Decimal Form: 10.19803902 …

Step-by-step explanation:

8 0
3 years ago
Q2) The following travel times were measured for vehicles traversing a 2,000 ft. segment of an arterial: Vehicle Travel Time (s)
adelina 88 [10]

Answer:

TMS = 45.78 m/s

SMS = 45.66 m/s

Step-by-step explanation:

Vehicle Travel Time (s)

1 40.5

2 44.2

3 41.7

4 47.3

5 46.5

6 41.9

7 43.0

8 47.0

9 42.6

10 43.3

Time mean speed and space mean speed are parameters used to express the speed of a group of vehicles in traffic flow.

Time mean speed is given as the average speed of all the cars

The speed for each vehicle is calculated by dividing the (2000 ft) distance by the time taken by each vehicle to complete that segment of the journey.

Let vehicle = V

Travel time = time

Speed = s

V | Time | speed (ft/s)

1 | 40.5 | 49.383

2 | 44.2 | 45.249

3 | 41.7 | 47.962

4 | 47.3 | 42.283

5 | 46.5 | 43.011

6 | 41.9 | 47.733

7 | 43.0 | 46.512

8 | 47.0 | 42.553

9 | 42.6 | 46.948

10| 43.3 | 46.189

TMS = (Σsᵢ)/N

Σsᵢ = (49.383+45.249+47.962+42.283+43.011+47.733+46.512+42.553+46.948+46.189)

Σsᵢ = 457.823

N = number of vehicles = 10

TMS = 457.823 ÷ 10 = 45.7823 = 45.782 m/s

b) Space mean speed is given as

SMS = N ÷ [Σ (1/sᵢ)]

V | Time | speed | (1/sᵢ)

1 | 40.5 | 49.383 | 0.02025

2 | 44.2 | 45.249 | 0.02210

3 | 41.7 | 47.962 | 0.02085

4 | 47.3 | 42.283 | 0.02365

5 | 46.5 | 43.011 | 0.02325

6 | 41.9 | 47.733 | 0.02095

7 | 43.0 | 46.512 | 0.02150

8 | 47.0 | 42.553 | 0.02350

9 | 42.6 | 46.948 | 0.02130

10| 43.3 | 46.189 | 0.02165

Σ (1/sᵢ) = (0.02025+0.02210+0.02085+0.02365+0.02325+0.02095+0.02150+0.02350+0.02130+0.02165)

Σ (1/sᵢ) = 0.219

SMS = 10 ÷ [Σ (1/sᵢ)] = 10 ÷ 0.219

SMS = 45.662 m/s

Hope this Helps!!!

4 0
3 years ago
Find the volume of the square pyramid, given its slant height​
Reptile [31]

Answer:

Step-by-step explanation:

base length b = 32 cm

slant height L = 30 cm

 

height h = √(L²-(½b)²)

= √(30²-0.25·32²)

≅ 25.3771550809 cm

 

volume V = (⅓)b²h

= (⅓)32²·25.38

≅ 8662.07 cm³

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Liam is saving up to buy a new pair of Jordan's that cost
Andreyy89

Answer:

9 weeks

Step-by-step explanation:

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3 years ago
What is the area of the polygon given below
Bezzdna [24]

Answer: 287

Step-by-step explanation:

6 0
2 years ago
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