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3 years ago

How do you use parallel and perpendicular lines to solve real-world problems?

2 answers:

6 0

If you work construction it’s in blue print salon with different angles on where you would cut wood or weld metal together.

ASHA 777 [7]3 years ago

4 0

Answer:

In engineering, construction, and technical fields

Step-by-step explanation:

The use of parallel lines has many wide applications

For example, the parallel lines are important in science in preventing parallax errors in measuring, say the meniscus of the water in a glass.

Another use is in construction. The use of the plumb line shows if the object being built is straight or not. The principle is that the force of the pull acts downwards. Another example is the spirit lever. This can be used by builders to check if the surface is even or not.

In engineering, the properties are important in building bridges and other high-tension structures.

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Solve the following recurrence relation: <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

4 0

2 years ago

if the hypotenuse of a special triangle of 45 45 90 was 10 radical 6 how would u solve for the hypotenuse

Vinvika [58]

Just do it it’s quite easy

3 0

3 years ago

Quadrilateral PQRS is transformed by translating it 6 units to the right and then rotating it 90° clockwise

Elina [12.6K]

Answer:

(y, -x -6)

Step-by-step explanation:

The coordinates of PQRS is not given, however we'll assume the coordinates of PQRS to be (x,y)

The first transformation: 6 units right

$(x,y) -> (x + b, y)$

Where b = 6

So, the new coordinates will be

$(x + 6, y)$

The second transformation: 90° clockwise

$(x,y) -> (y,-x)$

So, the new coordinates will be

$(x + 6, y)-> (y, -x -6)$

Hence, the new coordinates of PQRS is (y, -x - 6)

7 0

3 years ago

How many more people can sit on four 777 aircrafts than on four 767 aircrafts?

user100 [1]

Answer:40

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

To graduate this semester, you must pass Statistics 314; and you estimate that you have an 85% chance of passing. You need to pa

Nitella [24]

Answer:

Probability of graduating this semester is 0.7344

Step-by-step explanation:

Given the data in the question;

let A represent passing STAT-314

B represent passing at least in MATH-272 or MATH-444

M1 represent passing in MATH-272

M2 represent passing in MATH-444

C represent passing GERMAN-32

now

P( A ) = 0.85, P( C ) = 90, P( M1 ) = P( M2 ) = 0.8

P( B ) = P( pass at least one of either MATH-272 or MATH-444 ) = P( pass in MATH-272 but not MATH-444 ) + ( pass in MATH-444 but not in MATH 272) + P( pass both )

P( B ) = P( M1 ) × ( 1 - P( M2 ) ) + ( 1 - P( M1 ) ) × P( M2 ) + P( M1 ) × P( M2 )

we substitute

⇒ 0.8×0.2 + 0.2×0.8 + 0.8×0.8 = 0.16 + 0.16 + 0.64 = 0.96

∴ the probability of graduating this semester will be;

⇒ P( A ) × P( B ) × P( C )

we substitute

⇒ 0.85 × 0.96 × 90

⇒ 0.7344

Probability of graduating this semester is 0.7344

6 0

3 years ago