Answer:
Volume = 2384.582 cm^3
Surface Area = 189.626 cm^2
Step-by-step explanation:
With the accuracy of r within 0.6 cm minimum & maximum values are 25-0.3 and 25+0.3 respectively.
Taking r = 25 cm
Volume = (4/3)*Pi*R3 = 65449.847
Surface Area = 4*Pi*R2 = 7853.982
The minimum possible values for Volume and surface area would be:
if r = 24.7 cm
Volume = (4/3)*Pi*R3 = 63121.814 cm^3
Surface Area = 4*Pi*R2 = 7666.617 cm^2
The maximum possible values for Volume and surface area would be:
if r = 25.3 cm
Volume = (4/3)*Pi*R3 = 67834.429 cm^3
Surface Area = 4*Pi*R2 = 8043.608 cm^2
Error from Minimum values:
Volume = 2328.033 cm^3
Surface Area = 187.365 cm^2
Error from Maximum values:
Volume = 2384.582 cm^3
Surface Area = 189.626 cm^2
Answer:
Step-by-step explanation:
y = - 9
y^2 = (-9)^2 = 81
AND
z = 0.7
z^2 = (0.7)^2 = 0.49
Hope it helped
Answer:
b
Step-by-step explanation:
120
OA = OB
angle OAN = 90 degrees, so OAB and OBA is both 30 degrees.
Answer:


Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:
We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.
Step-by-step explanation:
We have the following info given:
represent the sampel mean for the age of customers
represent the population standard deviation
represent the sample size selected
We want to test if the mean age of her customers is over 35 so then the system of hypothesis for this case are:
Null hypothesis: 
Alternative hypothesis 
The statistic for this case is given by:

And replacing the data given we got:

We can calculate the p value since we are conducting a right tailed test like this:

Since the p value is lower than the significance level given of 0.05 we have enough evidence to reject the null hypothesis on this case. And the best conclusion for this case is:
We (reject) the null hypothesis. That means that we (found) evidence to support the alternative.