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irakobra [83]
3 years ago
13

Joan waters her plants with 25 1/2 gallons of water. With a new irrigation system in place, she uses 19 3/4 gallons of water eac

h day. How many gallons of water does she save in a 30-day period with the irrigation system?
Mathematics
1 answer:
leva [86]3 years ago
4 0

Answer:45,fty

Step-by-step explanation:

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Plzz i really need this plzz no aubsurd answers
lord [1]

Answer:

Step-by-step explanation:

7.

y= -2x+2

8.

y= -x-3

9.

y= 2/3 x + 1

10.

I'd put a point on (0, 15) , (1, 30), (2, 45) and etc....

Use a ruler to connect these points and use it to draw a straight line that hits all these points.

Good luck

6 0
3 years ago
HELP ME PLEASEE ASAP!!!! PLEASEE
11111nata11111 [884]

Answer:

<h2>25</h2>

Step-by-step explanation:

So there is this property,

Sum of two angle of triangle = exterior angle

So based on this we can form an algebraic equation (NOTE: this is an equilateral triangle so all the sides are 60°)

4x + 20 = 60 + 60 \\ 4x = 120 - 20 \\ 4x = 100 \\ x =  \frac{100}{4}  \\ x = 25

So it's option B.

6 0
3 years ago
Find the volume of a cylinder that has a diameter of 6 and a height of 9. Leave your answer in terms for pi.
Gekata [30.6K]

the volume maybe is 1017.88

6 0
3 years ago
Chloe needed to get her computer fixed. She took it to the repair store. The technician
CaHeK987 [17]

Answer:

he took $55.8for 1hr

Step-by-step explanation:

it's because we should devid eit for calculation for minute

3 0
3 years ago
A submersible traveling at a depth of 250 feet dives at an angle of 15 degrees with respect to a
kipiarov [429]

Answer:

\boxed{\text{652 ft}}

Step-by-step explanation:

The submersible is diving at a down angle of 15° along the hypotenuse AC of triangle ABC.  

Its horizontal track along the surface AB is 1500 ft.

\begin{array}{rcl}\tan A & = &\dfrac{BC}{AC}\\\\\tan 15^{\circ} & = & \dfrac{a}{1500}\\\\0.2679 & = & \dfrac{a}{1500}\\\\a & = & 1500 \times 0.2679\\& = & \textbf{402 ft}\\\end{array}

The submersible was already at a depth of 250 feet when it began the dive.

New depth = 250 + 402 = 652 ft

\text{The depth after the dive is }\boxed{\textbf{652 ft}}

6 0
3 years ago
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