All categories

3 years ago

Pls help i hope u guys have god and amazing day

Mathematics

1 answer:

ra1l [238]3 years ago

5 0

Answer:

A.) -1.0 or -1/1

B.) 0.75 or 3/4

C.) 0.25 or 1/4

D.) -1.25 or -5/4

You might be interested in

Characteristics of Polynomials

Andreas93 [3]

D.) A polynomial cannot have a variable in the denominator.

3 0

2 years ago

Read 2 more answers

Solve 7(x + 2) = -49

nata0808 [166]

Answer:

x= -9

Step-by-step explanation:

7(x+2)=-49

divide both sides by 7

(x+2)=-7

subtract 2 from both dies

x= -9

3 0

3 years ago

Read 2 more answers

An equation parallel and perpendicular to 4x+5y=19

UNO [17]

Answer:

Parallel line:

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

$y=\frac{5}{4}x-\frac{1}{2}$

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

$4x+5y=19$

we can change it into y=mx+b form

$5y=-4x+19$

$y=-\frac{4}{5}x+\frac{19}{5}$

so,

$m=-\frac{4}{5}$

Parallel line:

we know that slope of two parallel lines are always same

so,

$m'=-\frac{4}{5}$

Let's assume parallel line passes through (1,1)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-1=-\frac{4}{5}(x-1)$

now, we can solve for y

$y=-\frac{4}{5}x+\frac{9}{5}$

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

$m'=\frac{5}{4}$

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

$y-y_1=m'(x-x_1)$

we can plug values

$y-2=\frac{5}{4}(x-2)$

now, we can solve for y

$y=\frac{5}{4}x-\frac{1}{2}$

4 0

3 years ago

On a number line, point A has a coordinate of -6, and point B has a coordinate of 2. Which is the coordinate of point M, the mid

damaskus [11]

In my opinion
The answer is B

5 0

2 years ago

Giveng (x) = 6x – 19whatisg (25)?

abruzzese [7]

Answer:

131

Step-by-step explanation:

x=6(25)-19

x=150-19

x=131

7 0

3 years ago