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2 years ago

Y=2x-5 -3x - 4y=-2

Mathematics

1 answer:

Whitepunk [10]2 years ago

8 0

Answer:

y=-x/5 =3/5. that is how it is.

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What is the probability of drawing a king, then an ace (with replacement)?

alexandr1967 [171]

Answer:

So there is a 2 in 13 chance to pull out either an ace or king from the deck

Step-by-step explanation:

3 0

2 years ago

Help really needed! Thank you to whoever helps!

lana66690 [7]

2•2.5=3•-7 I'm not sure honestly that's my best guess

5 0

2 years ago

Simplify the expression. write the answer using scientific notation 4(6.2x10^11)

Veseljchak [2.6K]

Answer:
= 2.48 × 10¹²
(scientific notation)

= 2.48e12
(scientific e notation)

= 2.48 × 10¹²
(engineering notation)
(trillion; prefix tera- (T))

= 2480000000000
<span>(real number)</span>

7 0

3 years ago

Read 2 more answers

Given: m∠EYL=72°<br> Find: mEHL , mLVE

White raven [17]

Answer:

Part 1) The measure of arc EHL is $108\°$

Part 2) The measure of angle LVE is $54\°$

Step-by-step explanation:

step 1

Let

x-----> the measure of arc EHL

y----> the measure of arc EVL

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

$m$

we have

$m$

substitute

$72\°=\frac{1}{2}(y-x)$

$144\°=(y-x)$

$y=144\°+x$ ------> equation A

Remember that

$x+y=360\°$ -----> equation B ( complete circle)

substitute equation A in equation B and solve for x

$x+(144\°+x)=360\°$

$2x=360\°-144\°$

$x=216\°/2=108\°$

Find the value of y

$y=144\°+x$

$y=144\°+108\°=252\°$

therefore

The measure of arc EHL is $108\°$

The measure of arc EVL is $252\°$

step 2

Find the measure of angle LVE

we know that

The inscribed angle measures half that of the arc comprising

Let

x-----> the measure of arc EHL

$m$

we have

$x=108\°$

substitute

$m$

3 0

3 years ago

Find the solutions of the quadratic equation -9c² +2 +3 = 0.

Tresset [83]

Given that,

An equation : -9c² +2c +3 = 0

To find,

Find the value of x.

Solution,

We have, -9c² +2c +3 = 0

We can solve it using the formula as follows :

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here, a = -9, b = 2 and c =3

Put the values,

$c=\dfrac{-2\pm \sqrt{(2)^2-4(-9)(3)}}{2(-9)}\\\\c=\dfrac{-2+\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}, \dfrac{-2-\sqrt{(2)^{2}-4(-9)(3)}}{2(-9)}\\\\c=-0.47, 0.69$

So, the solution are -0.47 and 0.69.

8 0

2 years ago