Answer:
2
Step-by-step explanation:
the one which is near to x
Answer:
a) 0.0167
b) 0
c) 5.948
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.16 ounces
Standard Deviation, σ = 0.08 ounces
We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.
Formula:
a) Standard deviation of 23 bags

b) P( fill volume of 23 bags is below 5.95 ounces)
P(x < 5.95)
Calculation the value from standard normal z table, we have,
c) P( fill volume of 23 bags is below 6 ounces) = 0.001
P(x < 6) = 0.001
Calculation the value from standard normal z table, we have,


If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
PLEASE SEE ATTACHED IMAGE.
First, we define the variables:
x: number of years after 1950
f (x): amount of vinyl sold.
Then, with the variables defined, we have:
68594 vinyl records were sold in 1958 ---------> f (8) = 68594
91299 vinyl records were sold in 1961 ---------> f (11) = 91299
38720 vinyl records were sold in 1952 ---------> f (2) = 38720
161743 vinyl records were sold in 1967 ---------> f (17) = 161743
If i understand you are wanting to find the value of g
so if 2/5 of the unkown value g is equal to -14 you would find out that 1/5 g would be -7 so to find g you times -7 by 5 and get -35
g= -35