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NARA [144]
4 years ago
9

Write the number in exponent form

Mathematics
1 answer:
den301095 [7]4 years ago
6 0

3.\\\dfrac{-(2)(2)}{(-6)(-6)(-6)}=\dfrac{-(2)(2)}{-(2)(3)(2)(3)(2)(3)}=\dfrac{1}{(2)(3)(3)(3)}=\dfrac{1}{(2)(3^3)}\\\\=2^{-1}\cdot3^{-3}\\\\4.\\-(3)(3)(-5)(-5)=-(3)(3)(5)(5)=-3^2\cdot5^2=-(3\cdot5)^2=-15^2

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Solve the equation. 31-12n=211​
Mashutka [201]

Answer:

Step-by-step explanation:

31 - 12n = 21l              Subtract 31 from both sides.

31-31-12n =211-31       Do the subtraction

-12n = 190                  Divide by -12

-12n/-12 = 190/-12

n = -15.333333

6 0
4 years ago
Plz help quick will give brainly
miskamm [114]

Answer:

Opposite 12= -12

Absolute value of 12: Just -12.

Step-by-step explanation:

I don't know.

7 0
3 years ago
A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2 :
stiks02 [169]

Answer:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated proportion for this case is:

\hat p =\frac{322-306}{322}= 0.0497

Represent the proportion of defectives for this case

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.0497 - 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.026

0.0497 + 1.96\sqrt{\frac{0.0497(1-0.0497)}{322}}=0.073

The 90% confidence interval would be given by (0.026;0.073)

3 0
3 years ago
What is the ratio for 44 students and 6 adults?
zysi [14]
It would be: 44/6 = 22/3

In short, Your Answer would be 22 : 3

Hope this helps!
5 0
3 years ago
George was weighed at the doctors office. The scale read 67.20 pounds. The doctor wrote 67.2 on George’s chart. Did the doctor m
nata0808 [166]
No because 67.20 rounded to the nearest tenth is 67.2
8 0
3 years ago
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