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sukhopar [10]
2 years ago
15

) Una compañía invierte $15,000 al 8% y $22,000 al 9%. ¿A qué tasa debe invertir

Mathematics
1 answer:
Anna35 [415]2 years ago
7 0

Usando proporciones, hay que los $12,000 restantes deben ser investidos a una tasa de 11%.

<h3>¿Qué es una proporción?</h3>

Una proporción es una fracción de la cantidad total.

De las dos primeras inversiones, el ingreso es dado por:

0.08 x 15000 = $1,200.

0.09 x 22000 = $1,980

T = 1200 + 1980 = $3,180

Por la tercera inversión, busca-se un retorno de 4500 - 3180 = $1,320.

De esa forma, la tasa x es la seguiente:

12000x = 1320

x = 1320/12000

x = 0.11.

Los $12,000 restantes deben ser investidos a una tasa de 11%.

Puede-se aprender mas a cerca de proporciones es brainly.com/question/26425852

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The second one would be the correct option.

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Select the two values of x that are roots of this equation.<br> X2 + 2x - 5 = 0
LenaWriter [7]

Answer:

x=-1+\sqrt{6 }

x=-1-\sqrt{6 }

Step-by-step explanation:

x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

Ignore the A before the ±. It wouldn't let me type it correctly.

x² + 2x - 5 = 0

a = 1

b = 2

c = - 5

x=\frac{-2±\sqrt{2^{2}-4((1)(-5)) } }{2(1)}

x=\frac{-2±\sqrt{4-4((1)(-5)) } }{2(1)}

x=\frac{-2±\sqrt{4+20 } }{2(1)}

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x=\frac{-2±\sqrt{(2)(12) } }{2}

x=\frac{-2±\sqrt{(2)(2)(6) } }{2}

x=\frac{-2±\sqrt{(2)(2)(2)(3) } }{2}

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Two separate equations

x=\frac{-2+2\sqrt{6 } }{2}

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