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Andrew [12]
3 years ago
13

Solve the following equation on the interval [0,2 \pi) Cot(3x)=\sqrt{3}

Mathematics
1 answer:
Orlov [11]3 years ago
4 0
Cot(3x)=3^(1/2)

cot(x)= cos(x)/sin(x)

cot(3x)= cos(3x)/sin(3x)

look at a unit circle chart

find a value for cos that has sqrt(3) in it

which one will reduce so that the cos/sin will equal sqrt(3)?

pi/6 radians

now cot(3x) implies that x is one third this value

pi/18 is the answer
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Step-by-step explanation:

x > -1

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4 0
2 years ago
What is the solution of 9x-8=34x-12
Cerrena [4.2K]

Answer: x = 2/13

Step-by-step explanation:

9x-8=34x-12

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x = 2/13

4 0
3 years ago
How do i get the method on how to solve this x+5(-2)-1
galben [10]

Answer:

I forgot the name but I can show you how to do it lol

Step-by-step explanation:

x+5(-2)-1

x-10-1 we multiplied 5 and -2

x-11

x=11

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8 0
2 years ago
a triangle with a perimeter of 36 inches is dilated with a scale factor of 2. what will be the perimeter of the image
sweet [91]

Answer:

18

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7 0
3 years ago
Please assist me with this problem​
n200080 [17]

Answer:

The answer to your question is 90 dB

Step-by-step explanation:

Data

I = 10⁻³

I⁰ = 10⁻¹²

Formula

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Process

1.- To solve this problem, just substitute the values in the equation and do the operations.

2.- Substitution

     Loudness = 10 log (\frac{10^{-3}}{10^{-12}} )

3.- Simplify

      Loudness = 10log (1 x 10⁹)

      Loudness = 10(9)

      Loudness = 90

7 0
3 years ago
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