The numbers are (-8, 3) or (3, -8).
Step-by-step explanation:
- Step 1: Given the product of the numbers are -24 and their sum are -5. Let the numbers be a and b. Form equations out of these details.
⇒ a + b = -5 ⇒ b = -5 - a
⇒ a × b = -24 -------- (1)
- Step 2: Substitute the value of b in eq(1)
⇒ a × (-5 - a) = - 24
⇒ -5a - a² = -24
⇒ a² + 5a - 24 = 0
- Step 3: Solve the quadratic equation for a.
a = (-5 ± √25 - 4 × 1 × -24)/2
= (-5 ± √121)/2
= - 16/2, 6/2 = -8 or 3
- Step 4: For each value of a, find b.
When a = -8, b = -5 +8 = 3
When a = 3, b = -5 - 3 = -8.
Answer: 46
Step-by-step explanation:
You can simplify this using PEMDAS:
Parentheses
Exponents
Multiplication/division
Addition/subtraction
Move through the steps in that order.
In this case, the first two steps are absent, so multiply first:
20 - 16 + 42
Then, add and subtract:
46.
Answer:
Step-by-step explanation:
You have to show us the graph or chart before we can answer your questions
(cube root of 5) * sqrt(5)
--------------------------------- = ?
(cube root of 5^5)
This becomes easier if we switch to fractional exponents:
5^(1/3) * 5^(1/2) 5^(1/3 + 1/2) 5^(5/6)
------------------------ = --------------------- = ------------- = 5^[5/6 - 5/3]
[ 5^5 ]^(1/3) 5^(5/3) 5^(5/3)
Note that 5/6 - 5/3 = 5/6 - 10/6 = -5/6.
1
Thus, 5^[5/6 - 5/3] = 5^(-5/6) = --------------
5^(5/6)
That's the correct answer. But if you want to remove the fractional exponent from the denominator, do this:
1 5^(1/6) 5^(1/6)
---------- * ------------- = -------------- (ANSWER)
5^(5/6) 5^(1/6) 5
