Rectangle ABCD was rotated 90° counterclockwise around the origin and then translated 8 units down.
S = n(a1 + an)/2
2S = n(a1 + an)
2S = na1 + nan
nan = 2S - na1
an = (2S - n a1)/n
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
Positive.
Step-by-step explanation:
When you see two negative signs directly next to each other (as shown in the given expression), it will become a positive sign:
7 - (-4) = 7 + 4 = 11
Positive is your answer.
* To be fair, even if there is only one negative sign, the answer will still be positive, however, I am assuming you are suggesting only the sign, and not the answer.
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The answer to your question is 95,460
