4) A f is continuous at x=c
5) B if f is not differentiable at x=c, then f is not continuous at x=c
(x - 2)²(x+1)
(x-2)(x-2)
multiply the two brackets together
(x)(x)=x^2
(x)(-2)=-2x
(-2)(x)=-2x
(-2)(-2)=4
x^2-2x-2x+4
x^2-4x+4
(x^2-4x+4)(x+1)
multiply the brackets together
(x^2)(x)=x^3
(x^2)(1)=x^2
(-4x)(x)=-4x^2
(-4x)(1)=-4x
(4)(1)=4
x^3+x^2-4x^2-4x+4x+4
Answer:
x^3-3x^2+4
Answer:
d) Squared differences between actual and predicted Y values.
Step-by-step explanation:
Regression is called "least squares" regression line. The line takes the form = a + b*X where a and b are both constants. Value of Y and X is specific value of independent variable.Such formula could be used to generate values of given value X.
For example,
suppose a = 10 and b = 7. If X is 10, then predicted value for Y of 45 (from 10 + 5*7). It turns out that with any two variables X and Y. In other words, there exists one formula that will produce the best, or most accurate predictions for Y given X. Any other equation would not fit as well and would predict Y with more error. That equation is called the least squares regression equation.
It minimize the squared difference between actual and predicted value.
Answer:
first option
Step-by-step explanation:
Given
f(x) = 
← factorise the numerator
= 
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at ( , 0 )
Thus
discontinuity at (- 4, - 11 ), zero at ( , 0 )
Are you trying to solve for c? if so c=8
