The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
We just need to <u>plug in 7 for B! </u>
Let's do it !
2 + (10 - 7)
<em>We always start with the parenthesis first ! It's just a rule in math :) </em>
10 - 7 = ?
10 - 7 = 3
Now we have ...
2 + 3
2 + 3 = 5
Your final answer is 5!
I hope I helped :) Just comment if you have any questions and remember to vote me "brainliest" if you like my answer !!!
Answer:
The Ration of length 2.0 meters to the length 1.2 meters = 5 : 3
Step-by-step explanation:
The given two length are 2.0 m and 1.2 m
Length L1 = 2.0 m And
Length L2 = 1.2 m
SO, The ratio of L1 : L2 = 
Or, The ratio of L1 : L2 = 
∴ The ratio of L1 : L2 = 
Hence The ratio of L1 : L2 is 5 : 3 Answer