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soldier1979 [14.2K]
3 years ago
7

SOLVE USING LONG DIVISION:

Mathematics
1 answer:
Artemon [7]3 years ago
8 0

Answer:

\frac{3x^2+7x-20}{x+4}=3x-5

Step-by-step explanation:

Long division:

Step 1:

We divide '3x²' by 'x' to get the first term of quotient.

⇒ \frac{3x^2}{x}=3x

Now, we multiply '3x' to (x+4)

⇒ 3x(x+4)=3x^2+12x

Now, we subtract 3x^2+12x from the given numerator 3x^2+7x-20. This gives,

=3x^2+7x-20-(3x^2+12x)\\=3x^2+7x-20-3x^2-12x\\=3x^2-3x^2+7x-12x-20\\=-5x-20

Step 2:

We divide the first term of the above result by 'x' again to get the second term of the quotient.

⇒ \frac{-5x}{x}=-5

Now, we multiply '-5' to (x+4)

⇒ -5(x+4)=-5x-20

Now, we subtract -5x-20 from the result obtained at the last of step 1 -5x-20. This gives,

-5x-20-(-5x-20)=-5x+5x-20+20=0

So, we stop division as we got a constant after subtraction. The constant is called the remainder and here the remainder is 0.

The quotient is our answer: 3x-5

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