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Oksanka [162]
3 years ago
11

What is the value of 5.7 × 108?

Mathematics
1 answer:
Afina-wow [57]3 years ago
3 0
The value of 5.7 x 10⁸ is 570,000,000 CHOICE C.

The value of 8⁴ is 8 * 8 * 8 * 8 = 4,096 CHOICE C.

Prime factorization of 1,260

1260 ÷ 2 = 630
  630 ÷ 2 = 315
  315 ÷ 3 = 105
  105 ÷ 3 =  35
    35 ÷ 5 =    7

2 x 2 x 3 x 3 x 5 x 7 CHOICE D.

Composite numbers are numbers that have more factors other than 1 and itself.

91 / 1 = 91
91 / 7 = 13      CHOICE C. 91 is a composite number.
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The expression to find the perimeter of a rectangle is 2(length + width). What is the perimeter, in units, of a rectangle of len
Allisa [31]
First you plug in the data to the formula. So it will be 2(1/3+1/2). You then want to add the fractions together but must first find the common denominator which will be 6. So it is 2(2/6+3/6). The fractions then add up to be 5/6. So all you have to do is multiply it by 2 to get 5/3 which simplifies to 1 2/3 so it is D. 
4 0
3 years ago
Read 2 more answers
PLEASE HELP
irina [24]

Answer:

12\sqrt{3} feet

Step-by-step explanation:

In a 30-60-90 triangle, the ratios of the side lengths of the triangle is 1:\sqrt{3} :2

Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.

First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

\frac{x}{3} * \sqrt{3} = \frac{\sqrt{3} x}{3} = 12

Solving for x, we find that

x=\frac{36}{\sqrt{3} } = \frac{36 * \sqrt{3} }{\sqrt{3} * \sqrt{3} } = \frac{36  \sqrt{3} }{3} = 12\sqrt{3}

So the length of the original pole would be 12\sqrt{3} feet

If you found this answer helpful, please consider marking it as brainliest, or give it a thanks and a 5 star review. Thanks!

6 0
3 years ago
An Archer shoots an arrow horizontally at 250 feet per second. The bullseye on the target and the arrow are initially at the sam
Genrish500 [490]

Answer:

<h2>1.84feet</h2>

Step-by-step explanation:

Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;

Range R = U\sqrt{\frac{H}{g} }

U is the velocity of the arrow

H is the maximum height reached = distance below the bullseye reached by the arrow.

R is the horizontal distance covered i.e the distance of the target from the archer.

g is the acceleration due to gravity.

Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?

On substitution,

60 = 250\sqrt{\frac{H}{32}} \\\frac{60}{250} = \sqrt{\frac{H}{32}}\\\frac{6}{25} = \sqrt{\frac{H}{32}

Squaring both sides we have;

(\frac{6}{25} )^{2} = (\sqrt{\frac{H}{32} } )^{2} \\\frac{36}{625} =  \frac{H}{32} \\625H = 36*32\\H = \frac{36*32}{625} \\H = 1.84feet

The arrow will hit the target 1.84feet below the bullseye.

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3 years ago
Consider a function of the form f(x) = 7x^2 + ax, where a is a real number. What is the difference quotient of f(x) for all nonz
mihalych1998 [28]

Answer:

c

Step-by-step explanation:

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What is 1189^2 x 1809
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Answer:

the answer is : 2557421289

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