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3 years ago

15

Darren teaches a class of 25 students. He assigns homework 3 times a week, and each assignment consists of 12 problems. How many

problems must Darren correct each week?

1 answer:

Pie3 years ago

5 0

12 problems in each assignment and he assigns the assignments 3 times a week. He has 25 students. Therefor...

12 x 3 = 36

36 x 25 = 900

Answer: 900

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The volume of the triangluar block is 4 cubic inches. What is the approximate length of y?

Artist 52 [7]

The volume of the triangluar block is 4 cubic inches. What is the approximate length of y? -- 2.8 inches

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3 years ago

A survey was conducted to find out how much time people have to spend commuting to work. The sample means for two samples are 71

Lorico [155]

Answer:

E: None of the above

Step-by-step explanation:

Hello!

The objective is to find out how much time it takes people to commute to work.

Two samples where taken and two hypothesis tests where made:

One:

Sample mean 71 min; p-value: 0.03

Two:

Sample mean 72 min; p-value: 0.06

You have to choose from the options, a possible pair of hypotheses used for these two tests.

The parameter of the study is the population mean μ.

In the statistic hypotheses, the parameters are given either a known population value or a suspected value. So all options including sample values are wrong.

As said before the objective of the survey is to "determine how much time people spend commuting to work" in other words, whether or not the population mean is equal to a certain value.

H₀: μ = μ₀

H₁: μ = μ₀

Where μ₀ represents the theoretical value of the population mean. As you can say the hypotheses pair is two-tailed, not one-tailed.

Then the correct answer is E: None of the above

I hope this helps!

7 0

3 years ago

A bookstore sells books at 25% profit calculate the percentage of sales price to cost price ?

g100num [7]

Answer:

Cost price=100%

Step-by-step explanation:

3 0

2 years ago

Differentiate the following functions (x^3+1)(x-2)÷x^2

Masja [62]

Given:

The given function is:

$\dfrac{(x^3+1)(x-2)}{x^2}$

To find:

The differentiation of the given function.

Solution:

Consider the given function,

$y=\dfrac{(x^3+1)(x-2)}{x^2}$

It can be written as:

$y=\dfrac{(x^3)(x)+(x^3)(-2)+(1)(x)+(1)(-2)}{x^2}$

$y=\dfrac{x^4-2x^3+x-2}{x^2}$

$y=\dfrac{x^4}{x^2}-\dfrac{2x^3}{x^2}+\dfrac{x}{x^2}-\dfrac{2}{x^2}$

$y=x^2-2x+\dfrac{1}{x}-\dfrac{2}{x^2}$

Differentiate with respect to x.

$y'=\dfrac{d}{dx}(x^2)-\dfrac{d}{dx}(2x)+\dfrac{d}{dx}(x^{-1})-\dfrac{d}{dx}\2(x^{-2})$

$y'=2x-2(1)+(-x^{-2})-2(-2x^{-3})$

$y'=2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$

Therefore, the differentiation of the given function is $2x-2-\dfrac{1}{x^2}+\dfrac{4}{x^3}$ .

8 0

3 years ago

A bag contains red marbles, white marbles, and blue marbles. Randomly choose two marbles, one at a time, and without replacement

dsp73

Answer:

$P(First\ White\ and\ Second\ Blue) = \frac{3}{28}$

$P(Same) = \frac{67}{210}$

Step-by-step explanation:

Given (Omitted from the question)

$Red = 7$

$White = 9$

$Blue = 5$

Solving (a): $P(First\ White\ and\ Second\ Blue)$

This is calculated using:

$P(First\ White\ and\ Second\ Blue) = P(White) * P(Blue)$

$P(First\ White\ and\ Second\ Blue) = \frac{n(White)}{Total} * \frac{n(Blue)}{Total - 1}$

<em>We used Total - 1 because it is a probability without replacement</em>

So, we have:

$P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{21 - 1}$

$P(First\ White\ and\ Second\ Blue) = \frac{9}{21} * \frac{5}{20}$

$P(First\ White\ and\ Second\ Blue) = \frac{9*5}{21*20}$

$P(First\ White\ and\ Second\ Blue) = \frac{45}{420}$

$P(First\ White\ and\ Second\ Blue) = \frac{3}{28}$

Solving (b) $P(Same)$

This is calculated as:

$P(Same) = P(First\ Blue\ and Second\ Blue)\$ $or\ P(First\ Red\ and Second\ Red)\ or\ P(First\ White\ and Second\ White)$

$P(Same) = (\frac{n(Blue)}{Total} * \frac{n(Blue)-1}{Total-1})+(\frac{n(Red)}{Total} * \frac{n(Red)-1}{Total-1})+(\frac{n(White)}{Total} * \frac{n(White)-1}{Total-1})$

$P(Same) = (\frac{5}{21} * \frac{4}{20})+(\frac{7}{21} * \frac{6}{20})+(\frac{9}{21} * \frac{8}{20})$

$P(Same) = \frac{20}{420}+\frac{42}{420} +\frac{72}{420}$

$P(Same) = \frac{20+42+72}{420}$

$P(Same) = \frac{134}{420}$

$P(Same) = \frac{67}{210}$

6 0

2 years ago