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Neko [114]
3 years ago
10

Which values or value are the expressions 15k + 9 and 3(2k + 3) +9k equivalent to?

Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0
So im going to factor each expressions
15k + 9 are both divisible by 3 so it is the same as
3(5k+3) (distribute the 3 and you get your original equation)
3(2k+3) +9k
6k+9+9k
15K+9 and do the same thing above
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Step-by-step explanation:

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marcys breakfast table has a square table top with an area of 36 square feet. what is the diagonal length of the table top​
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A ball is thrown into the air with a velocity of 34 ft/s. It's height in feet after t seconds is given by y=34t-26(t)^2. Find th
kkurt [141]

Answer:

The average velocity of the ball at the given time interval is -122.3 ft/s

Step-by-step explanation:

Given;

velocity of the ball, v = 34 ft/s

height of the ball, y = 34t - 26t²

initial time, t₀ = 3 seconds

final time, t = 3 + 0.01 = 3.01 seconds

At t = 3 s

y(3) = 34(3) - 26(3)² = -132

The average velocity of the ball in ft/s is given as;

V_{avg} = \frac{y(3.01)-y(3)}{3.01 -3}\\\\V_{avg} = \frac{34(3.01)-26(3.01)^2-y(3)}{3.01 -3}\\\\V_{avg} = \frac{-133.223-y(3)}{0.01}\\\\V_{avg} = \frac{-133.223-(-132)}{0.01}\\\\V_{avg} =\frac{-1.223}{0.01}\\\\V_{avg} = -122.3 \ ft/s

Therefore, the average velocity of the ball at the given time interval is -122.3 ft/s

8 0
3 years ago
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