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s344n2d4d5 [400]
2 years ago
13

Write the equation of the graph shown below in factored form. a graph that starts at the top left and continues down through the

x axis at one to a minimum around y equals negative zero point six and goes up to cross the x axis two to a maximum around y equals zero point two and and then goes back down to a touch the x axis at three and then goes back up to the top right. f(x) = (x − 3)2(x + 2)(x − 1) f(x) = (x + 3)2(x − 2)(x + 1) f(x) = (x + 3)2(x + 2)(x + 1) f(x) = (x − 3)2(x − 2)(x − 1)
Mathematics
1 answer:
Brut [27]2 years ago
8 0

Answer:

  (d)  f(x) = (x − 3)^2(x − 2)(x − 1)

Step-by-step explanation:

In this context, a crossing of the axis at x=p means there is a factor of (x-p). A "touch" of the axis at x=q means there is a factor of (x -q)^2.

A crossing at x=1 and x=2, and a touch at x=3 means the factors are ...

  f(x) = (x -1)(x -2)(x -3)^2 . . . . . matches the last choice

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