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s344n2d4d5 [400]
2 years ago
13

Write the equation of the graph shown below in factored form. a graph that starts at the top left and continues down through the

x axis at one to a minimum around y equals negative zero point six and goes up to cross the x axis two to a maximum around y equals zero point two and and then goes back down to a touch the x axis at three and then goes back up to the top right. f(x) = (x − 3)2(x + 2)(x − 1) f(x) = (x + 3)2(x − 2)(x + 1) f(x) = (x + 3)2(x + 2)(x + 1) f(x) = (x − 3)2(x − 2)(x − 1)
Mathematics
1 answer:
Brut [27]2 years ago
8 0

Answer:

  (d)  f(x) = (x − 3)^2(x − 2)(x − 1)

Step-by-step explanation:

In this context, a crossing of the axis at x=p means there is a factor of (x-p). A "touch" of the axis at x=q means there is a factor of (x -q)^2.

A crossing at x=1 and x=2, and a touch at x=3 means the factors are ...

  f(x) = (x -1)(x -2)(x -3)^2 . . . . . matches the last choice

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A child standing on a river bank ten feet above the river throws a toward the river at a speed of 12 feet per second . How long
Anastasy [175]
sure just give me head
8 0
2 years ago
If <br><img src="https://tex.z-dn.net/?f=36%20%5E%7B12%20-%20m%7D%20%3D%206%5E%7B2m%7D%20" id="TexFormula1" title="36 ^{12 - m}
Katyanochek1 [597]

Answer:

6

Step-by-step explanation:

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8 0
3 years ago
At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500
kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}

i.e. PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}

Substituting the values, we get,

i.e. PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}

i.e. 22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-0.4735]}{0.00625}

i.e. 22000=\frac{P\times 0.5265}{0.00625}

i.e. P=\frac{22000\times 0.00625}{0.5265}

i.e. P=\frac{137.5}{0.5265}

i.e. P=261.16

Thus, the total lifetime cost to pay of the loans compounded annually  = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0
3 years ago
Read 2 more answers
2 Points
Jobisdone [24]
The answer is a. $11 bc you divide the amount made by the hours worked
3 0
3 years ago
How many more unit tiles must be added to the function f(x)=x2−6x+1 in order to complete the square?
Valentin [98]
<h2>8 unit tiles should be added</h2>

Step-by-step explanation:

       Function given is f(x)=x^{2}-6x+1. We wish to add more unit tiles to the function so that it becomes a complete square.

       Since the given function is of order 2, the side of the square will be order 1. Let us assume a general order 1 expression ax+b to be the side of the square.

       As the function forms the square after adding some p unit tiles, f(x)+p=(\text{Side of square})^{2}

x^{2}-6x+1+p=(ax+b)^{2}=a^{2}x^{2} +2abx+b^{2}

From comparision, a^{2}=1; 2ab=-6; b^{2}=1+p\\a=1; b=-3\\(-3)^{2}=p+1\\p=8

∴ 8 more unit tiles are required to complete the square.

10 0
3 years ago
Read 2 more answers
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