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timama [110]
3 years ago
9

There are 9 members on a board of directors. If they must select a chairperson, a secretary, and a treasure, how many different

slates of candidates are possible?
Mathematics
1 answer:
crimeas [40]3 years ago
3 0
Given: 9 members
elect 1 chairperson
elect 1 secretary
elect 1 treasurer

there are 9 choices for a chairperson, 8 for a secretary, and 7 for a treasurer.
9*8*7 = 504.
therefore, there are 504 different candidates possible
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\huge \boxed{\mathfrak{Question} \downarrow}

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\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

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