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PSYCHO15rus [73]
3 years ago
13

Select the correct answer.

Mathematics
1 answer:
V125BC [204]3 years ago
6 0

Answer:

R(x) = x + 9

Step-by-step explanation:

R(x) = x + 9 shifts the graph up 9 units.

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He difference of 29 and n
almond37 [142]

Answer:

28

Step-by-step explanation:

n can be represented as 1.

29 - 1 = 28

Please visit my church's website at fbcinterlaken.org to learn more about God. Please subscribe to the You Tube channel because my church really needs the support right now. Thank you! And have a nice day! :) (I will take brainliest).

3 0
2 years ago
Read 2 more answers
Please Help!!! . . . . .
Ede4ka [16]
PEMDAS. parenthesis, exponents, multiple or divide (whichever come first from left to right), add or subtract (whichever comes first from left to right)

So first do stuff in parenthesis.
Then do divide because thats next on the list and it happens earlier than the multiply one.

So, A
8 0
2 years ago
Solve using Fourier series.
Olin [163]
With 2L=\pi, the Fourier series expansion of f(x) is

\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L
\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx

where the coefficients are obtained by computing

\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx
\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx

\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx
\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx

\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx
\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx

You should end up with

a_0=0
a_n=0
(both due to the fact that f(x) is odd)
b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)

Now the problem is that this expansion does not match the given one. As a matter of fact, since f(x) is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of f(x), which is to say we're actually considering the function

\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3

and enforcing a period of 2L=2\pi. Now, you should find that

\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)

The value of the sum can then be verified by choosing x=0, which gives

\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)
\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots

as required.
5 0
3 years ago
Given h(x) = -X – 2, solve for x when h(x) = 3.
Naya [18.7K]
The answer should be h(3)= -5
6 0
3 years ago
Read 2 more answers
Let a,b,c ∈ Z. Define the highest common factor hcf(a,b,c) to be the largest positive integer that divides a,b and c. Prove that
kakasveta [241]

21 they have too be right next to each other and threy have too be right

8 0
3 years ago
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