Hey there!
So, therefore... the value 
in this number would be 
Answer:
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Answer:
No, it is greater
Step-by-step explanation:
The easiest way to find out is to make the two figures fraction and make the denominators the same.
7/20 * 50/50 > 305/1000
350/1000 > 305/1000
0.35 > 0.305
If we assume the hypotenuse is of side length 5:
a^2+b^2=c^2
3^2+b^2=5^2
9+b^2=25
b^2=16
b=4
If the hypotenuse is the unknown:
a^2+b^2=c^2
3^2+5^2=c^2
9+25=c^2
c^2=34
c=(34)^(1/2)
The probability of event A and B to both occur is denoted as P(A ∩ B) = P(A) P(B|A). It is the probability that Event A occurs times the probability that Event B occurs, given that Event A has occurred.
So, to find the probability that you will be assigned a poem by Shakespeare and by Tennyson, let Event A = the event that a Shakespeare poem will be assigned to you; and let Event B = the event that the second poem that will be assigned to you will be by Tennyson.
At first, there are a total of 13 poems that would be randomly assigned in your class. There are 4 poems by Shakespeare, thus P(A) is 4/13.
After the first selection, there would be 13 poems left. Therefore, P(B|A) = 2/12
Based on the rule of multiplication,
P(A ∩ B) = P(A) P(B|A)P(A ∩ B) = 4/13 * 2/12
P(A ∩ B) = 8/156
P(A ∩ B) = 2/39
The probability that you will be assigned a poem by Shakespeare, then a poem by Tennyson is 2/39 or 5.13%.
