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4 years ago

A video visual effects animator creates an animation by translating a logo using a coordinate

Mathematics

1 answer:

yan [13]4 years ago

5 0

Answer:

2nd one have a good day ;)

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The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

8 0

3 years ago

What does the median do in a box plot

iogann1982 [59]

Answer:

the median marks the middle or the mid-point of the data and is often shown by the line that divides the box into two parts.

Step-by-step explanation:

hope this helps:)

6 0

3 years ago

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Please help 20 points

zysi [14]

Answer:

i think 65 but if not then it is D impossible

Step-by-step explanation:

hope that helps

and that i wasn't to late

6 0

3 years ago

Pllllzzzzzzzzzzzzzzzz help me with this!!!!!!!!!!!!

Lorico [155]

Step-by-step explanation:

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4 0

3 years ago

Use the zero product property to find the solutions to the equation x^2-13x+30=0

Daniel [21]

We need to solve the zeroes of the given expression x² - 13x + 30 = 0 and we need to apply zero product property.First, we need to identify the two numbers which will result to -13 when added and it will result to 30 when multiplied. These two numbers are -3 and -10. Then, we can proceed with the solution such as:
x² - 13x + 30 = 0
(x-3) (x- 10) =0
From above, we have already the two zero product:
x-3 = 0
x1 = 3
x-10 =0
x2 =10

The answers are x1 = 3 and x2 = 10.

8 0

4 years ago

Read 2 more answers