List the domain and range of the relation. {(4-3), (8,8), (0.-3)(8.1) (4.3)} The domain is

Mathematics

1 answer:

Pavel [41]3 years ago

4 0

Answer:

(4,-3) Domain: 4. (8,8) Domain: 8. (0,-3) Domain: 0. (8,1) Domain: 8 (4,3) Domain: 4

You might be interested in

If susan is charged $175, how many days did susan rent A ski lift pass

Fudgin [204]

Answer:

Step-by-step explanation:

three days?

4 0

3 years ago

Read 2 more answers

Last year, a professional basketball team

jarptica [38.1K]

Answer:

15%

Step-by-step explanation:

Take 9 and divide that by 60.

8 0

2 years ago

How to find trigonomic ratio

ycow [4]

Answer:divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.

Step-by-step explanation:

divide the opposite sides, by the length of the hypotenuse. To get the cosine, divide the length of the adjacent side,by the length of the hypotenuse.

7 0

3 years ago

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$