1 out if 20 you would get right
There is 5 questions 4 answers to pick from so 5 times 4 is 20
Then they said what is the probability of only getting one answer right
So the answer would be 1 out of 20 1/20
Answer:
Coffee = $2.00
Juice = $1.50
Doughnut = $1.00
Step-by-step explanation:
Given
Let:

So, we have:
Anna

Barry

Cathy

Required
The price of each
We have:



Make c the subject in: 

Substitute
in
and 

![2[5.00 - 3d] + j + 2d = 7.50](https://tex.z-dn.net/?f=2%5B5.00%20-%203d%5D%20%2B%20j%20%2B%202d%20%3D%207.50)

Make j the subject



![3[5.00 - 3d] + j + 4d = 11.50](https://tex.z-dn.net/?f=3%5B5.00%20-%203d%5D%20%2B%20j%20%2B%204d%20%3D%2011.50)

Make j the subject


So, we have:
and 
Equate both values of j

Collect like terms


Substitute
in 




To solve for c, we substitute
in 


Solve for c


Perimeter = 2*(length +width)
perimeter = 2*(3x + (3x +(2x+6)))
.. = 2*(3x +3x +2x +6)
.. = 2*(8x +6)
perimeter = 16x +12
If x=3, the perimeter is 16*3 +12 = 60 inches.
You eliminate or ‘take away’ the answers that you know or think that r wrong. The last answer that’s left is your answer.
Each of the 5 saw 15 birds a day, so they saw 75 each day for 14 days. 75 times 14 is 1,050. They saw in total, 1,050 birds.