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Zolol [24]
3 years ago
9

Some one pleae help!

Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
7 0

Answer: \frac{61}{70}

Step-by-step explanation:

<em>let's take the two given distances and add them together</em>

<em />\frac{3}{10}+\frac{4}{7}<em />

<em>Now let's make give them a common denominator of 70</em>

<em>To do this we need to multiply </em>\frac{3}{10} (\frac{7}{7} ) and \frac{4}{7} (\frac{10}{10})<em />

<em />\frac{21}{70}+\frac{40}{70}<em />

<em />\frac{61}{70}<em />

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Please help ASAP!!!!!
padilas [110]

Answer:

18ft^2

Step-by-step explanation:

I'm going to use a dilation method to help solve this.

First we need to find your base. So 12/4 = 3.

6*3 = 18.

18 ft^2

7 0
4 years ago
What is the recursive formula for this sequence . 10,14,18,22,26,...
ad-work [718]
X+4 it is add 4 digit
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3 years ago
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Lynna [10]

60.2

Step-by-step explanation:

a^2 + b^2 = c^2

40^2 + 45^2 = c^2

1600 + 2025 = c^2

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6 0
3 years ago
Read 2 more answers
In an arithmetic sequence, find a50 when a1=7 and d=5<br> a. 495<br> b. 252<br> c. 275<br> d. 349
aksik [14]
An arithmetic sequence is an ordered list of numbers where the next number is found by adding the same amount to the number before. (2,5,8,11... is one where you add 3 to get the next number)
The equation for arithmetic sequence is
A_{n} = A_{1} +(n-1)d
where A_{n} is the "n th" number in the sequence
(A_{1} is the first number in the sequence)
d is the number you add to get the next number

<span>A_{n} = A_{1} +(n-1)d
</span><span>A_{50} = 7 +(50-1)(5)
</span><span>A_{50} = 7 +(49)(5)
</span><span>A_{50} = 7 +245
</span>A_{50} =252

The answer is B. 252
4 0
4 years ago
Line L has equation y = 4x - 7, and line M is parallel to line L and passes through the point (2, 15). Determine the equation of
yarga [219]

Answer:

y=4x+7

Step-by-step explanation:

Line M is parallel to line L, so the equation for line M is y=4x+b

Plug in the coordinates of point (2,15), you get:

15=4*2+b

Solve that to get b=7

Therefore the equation of Line M is y=4x+7

5 0
4 years ago
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