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2 years ago

The vertex form of the function y=x^2+8x+29

Mathematics

1 answer:

stira [4]2 years ago

5 0

Answer:

y = (x+4)^2 +13

Step-by-step explanation:

y=x^2+8x+29

To complete the square take the coefficient of the x term

Divide by 2

8/2 =4

Then square it

4^2 =16

y=x^2+8x+16+13

= (x^2+8x+16) +13

= (x+4)^2 +13

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Enter the fraction as a product of a whole number and a unit fraction. 9 10 =

nadya68 [22]

Answer:

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Step-by-step explanation:

8 0

2 years ago

What is the equation of the line that is parallel to the line x = –2 and passes through the point (–5, 4)?x = –5x = 4y = –5y = 4

Rainbow [258]

x = -5 is the equation of the line that is parallel to the line x = –2 and passes through the point (–5, 4)

Solution:

Given that, we have to write the equation of line that is parallel to line x = -2 and passes through point (-5, 4)

From given,

The equation of the line in standard form is x = -2

This is a vertical line, so the parallel line will also be a vertical line of the form:

x = a

Since we are given that the line should pass through the point (-5, 4) then the equation of the line is:

x = -5

Thus the equation of line is found

3 0

2 years ago

Read 2 more answers

The volume of the cone shown is 5 cubic inches. What is the height of a cone with the same base diameter but a volume of 10 cubi

MaRussiya [10]

Answer:

The height of the second cone is 2 h₁.

Step-by-step explanation:

The volume of a cone is:

$V=\pi\ r^{2}\frac{h}{3}$

The volume of the first cone is, V₁ = 5 in³.

The volume of the second cone is, V₂ = 10 in³.

The two cones have the same base diameters.

This implies that the two radii are same, i.e. r₁ = r₂.

Compute the height of the second cone as follows:

$r_{1}=r_{2}$

$\frac{3\cdot V_{1}}{\pi\ h_{1}}=\frac{3\cdot V_{2}}{\pi\ h_{2}}$

$\frac{V_{1}}{h_{1}}=\frac{V_{2}}{ h_{2}}$

$\frac{5}{h_{1}}=\frac{10}{h_{2}}$

$h_{2}=2\ h_{1}$

Thus, the height of the second cone is 2 h₁.

7 0

2 years ago

The slope of the line below is -2. Use the coordinates of the labeled point to

Vilka [71]

Answer:

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

Step-by-step explanation:

Incomplete question:

There is no point to complete the equation.

As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.

The linear equation can be written generically as:

$y(x)=mx+b\\\\y(x)=-2x+b$

If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:

$y_0=-2x_0+b$

Then, we can calculate b as:

$y_0=-2x_0+b\\\\b=y_0+2x_0$

We can express the equation for any linear equation with slope -2 and point (x0,y0) as:

$y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)$

6 0

3 years ago

The table represents the function f(x)=2x+1

elena-14-01-66 [18.8K]

Maybe try using Photomath it works for me. Good luck

4 0

3 years ago