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JulijaS [17]
3 years ago
6

The vertex form of the function y=x^2+8x+29

Mathematics
1 answer:
stira [4]3 years ago
5 0

Answer:

y = (x+4)^2 +13

Step-by-step explanation:

y=x^2+8x+29

To complete the square take  the coefficient of the x term

8

Divide by 2

8/2 =4

Then square it

4^2 =16

y=x^2+8x+16+13

 = (x^2+8x+16)  +13

 = (x+4)^2 +13

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6ft and 10ft =? it's the pythagorean theorem
anyanavicka [17]

Answer:

11.7

Step-by-step explanation:

pythagorean theorem is A^{2} +B^{2}=C^{2}

apply that same formula soo 6^{2} +10^{2}=136^{2}

then sqaure root 136\sqrt{136} =11.66190379

round that soo now the answer is 11.7

7 0
3 years ago
Read 2 more answers
Find the common difference of the arithmetic sequence -19, -16, -13, ...
Yuliya22 [10]

Answer:

d= +3

Step-by-step explanation:

1st term = -19

2nd term = -16

d = 2nd - 1st

d= -16-(-19)

d = +3

4 0
3 years ago
What is the area of the shaded segment?
Whitepunk [10]

Answer:

6\pi-9\sqrt{3

Step-by-step explanation:

The area of a pie-slice shape can be found with the equation A=\pi nr^2/360 where n is the angle of the shape and r is the radius of the circle. In this case, n=60 and r=6. Therefore, the total area of the pie-slice is \pi (60)(6^2)/360=6 \pi

Next, the triangle that makes up the unshaded part of the segment is an equilateral triangle because the angle is 60. The area of an equilateral triangle is \sqrt{3}r^2/4 where r is the length of one of its side (in this case, r=6). Plugging that in, we get an area of 9 \sqrt{3}

Finally, the area of the shaded is the area of the pie-slice minus the area of the triangle: 6\pi-9\sqrt{3

8 0
3 years ago
What are the soulutions to m^2-9=0
mihalych1998 [28]

Answer:

m= 3, -3

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
Read 2 more answers
How do you solve this
Dmitriy789 [7]

By definition of the trig functions,

\sin30^\circ=\dfrac y{16}

\cos30^\circ=\dfrac x{16}

We have \sin30^\circ=\dfrac12, so y=8, and \cos30^\circ=\dfrac{\sqrt3}2, so x=8\sqrt3.

Just to check: we should have

x^2+y^2=16^2

by the Pythagorean theorem. Indeed,

8^2+(8\sqrt3)^2=4\cdot8^2=2^2(2^3)^2=2^8=(2^4)^2=16^2

6 0
3 years ago
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