Answer:
No, the child cannot inherit the disease.
Explanation:
The problem tells you that the man has a recessive allele for an inherited disease, but he has a normal phenotype. This means that the disease is recessive and in order for an individual to have the disease, they must have two recessive copies of the allele. The problem also tells you that the mother has a genotype that does not include this allele. With this information, you can do a punnet cross of BB (mother) x Bb (carrier father), and end up with the following possible genotypes: BB, Bb, BB, Bb. Therefore the child will not have the disease, but there is a 50% chance that the child will be a carrier for the disease.
The phrase to fit into the blank is "sexual reproduction"!
In sexual reproduction each of the parents produces a gamete and contributes to half of the offspring's genes. This means that the offspring is a unique composition of the two parents.
In contrast, in a asexual reproduction, the offspring would likely have the same genetic code as the parent.
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You know that there is a difference between plant cells and animals cells. The plant cells have a cytoplasm while the animal cells do not. Therefore the answer must be C.
Answer:
pic 1 red giant, a star whose outer shell has expanded and cooled
pic 2: supernova, a shock wave produced by extremely high temperatures
pic 3: black hole, a high mass star that has collapsed from gravity
pic 4: white dwarf, a low mass star that has shed its outer layers
Explanation:
