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tiny-mole [99]
4 years ago
5

Does anyone know how to do all of this

Mathematics
1 answer:
jolli1 [7]4 years ago
7 0

Answer:

price paid of speakers= £40.5

price paid of headphones=£ 5.6

price paid of book=£6.65

price paid of mobile phone=£42

price paid of mouse=£ 15.75

price paid of DVD=£11.05

solution,

1. Cost of speakers:

Discount percent=10 %

Marked price=£45

discount amount= discount % of MP

=10% of 45

=£4.5

Selling price= MP - discount amount

=£45-£4.5

=£ 40.5

2. cost of headphones:

discount amount= discount% of MP

=20% of 7

=£1.4

Selling price= MP- Discount amount

=£7-£1.4

=£ 5.6

3. cost of books:

discount amount= discount percent of MP

= 30% Of 9.50

=£ 2.85

selling price= MP- Discount amount

= £ 9.50-£2.85

=£ 6.65

4. cost of mobile phone:

discount amount= discount% of MP

=40% of 70

=£ 28

selling price= MP- Discount amount

=£70-£28

=£ 42

5. cost of mouse:

discount amount= discount% of MP

= 25% of 21

=£ 5.25

selling price= MP- Discount amount

=£21-£5.25

=£ 15.75

6. cost of DVD:

discount amount= discount % of MP

= 15% of 13

= £ 1.95

selling price= MP- discount amount

=£ 13 -£ 1.95

=£ 11.05

Hope this helps...

Good luck on your assignment..

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Answer:

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<h2>200°</h2>

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\frac{10\pi}{9}  \times  \frac{180}{\pi}  \\  =  \frac{1800}{9}

We have the final answer as

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3 years ago
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<h2>Intersection and Union of Sets</h2><h3>Answer:</h3>

A \cup B = \{ a, b, c, d, e \}

B \cap C = \{ d, e \}

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<h3>Step-by-step explanation:</h3>

Given:

A = \{ a, b, c, d \}

B = \{ b, d, e \}

C = \{ d, e, f \}

The Union (\cup) of sets A and B is just a set containing all the elements of sets A and B. However, elements that are present in both sets should not repeat in the Union of Sets as the elements of a set should distinct be from each other.

Part i:

A \cup B \\ \{ a, b, c, d \} \cup \{ b, d, e \} \\ \{ a, b, c, d, e \}

The Intersection (\cap) of sets A and B is just a set containing all the elements that are both present in sets A and B.

Part ii:

B \cap C \\ \{ b, d, e \} \cap \{ d, e, f \} \\ \{ d, e \}

Part iii:

A \cup C \\ \{ a, b, c, d, \} \cup \{d, e, f \} \\ \{ a, b, c, d, e, f \}

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Answer:

Options (2) and (3)

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Rigid transformation like translation, rotation or reflection form the image with no change in the area or shape.

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If k > 1, area of the image will be greater than the original shape.

If 0 < k < 1, are of the image will be smaller than the original.

Option (1),

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Therefore, image will be smaller than the original.

Option (2)

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First dilation is by a scale factor of 2 and the second is by a scale factor of \frac{2}{3}.

By first dilation area of the image will get doubled.

Followed by the dilation by a scale factor of \frac{2}{3}, area of the image will be dilated by the scale factor = 2\times \frac{2}{3}

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Option (3)

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Since, \frac{3}{2}>1

Image will have the greater area than the original.

Option (4)

In this option polygon is dilated by a scale factor \frac{1}{2}.

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Options (2) and (3) will be the correct options.

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