He would save 70 cents because .10 x 7 = .7
and .7 x 100 is 70
I am thinking on this question hold up
The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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If two angles are equal, then they are both obtuse
Answer:
65/72
Step-by-step explanation:
cot is simply cosine over sine or the tangant flipped
the cos (c)=65/97
sin (c) = 72/97
cot would be (65/97)/(72/97)
How do you divide fractions? By multiplying the reciprocal!
cot would be 65/97 * 97/72
the 97s cross out.
65/72
