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Lelu [443]
4 years ago
6

The product of two consecutive negative integers is 1122. What are the numbers? The product of two consecutive negative integers

is 1122. What are the numbers? @Mathematics
Mathematics
1 answer:
saw5 [17]4 years ago
4 0
Let the two numbers be -x and -x - 1, then
-x(-x - 1) = 1,122
x^2 + x = 1,122
x^2 + x + 1/4 = 1,122 + 1/4
(x + 1/2)^2 = 4,489/4
x + 1/2 = sqrt(4,489/4) = + or -67/2
x = 67/2 - 1/2 = 66/2 = 33

Therefore, the two numbers are -33 and -34
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6 0
3 years ago
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Marrrta [24]
The answer is
4 5/8
3 0
3 years ago
Read 2 more answers
-2x-9y=-25 -4x-9y=-23 system with elimination
REY [17]
Multiply the first equation by -2. It turns into 4x+18y=50 and the other one stays -4x-9y=-23. Then you "eliminate" the equations by "adding" them. Set it up like this: 
4x+18y=50
      +
-4x-9y=-23
4x-4x= 0. 18y-9y= 9y and 50-23= 27
SO: 9y= 27 and y= 3
And then you plug that in to one equation: 4x +18(3)= 50. 4x= 50-(18*3)
4x= -4, so x=-1.
Plug it back in to check! 
Hope this helps. Happy solving! :)
4 0
3 years ago
Read 2 more answers
5) 3(8+ n) - 15 = 24
scoundrel [369]
•First you multiply parentheses by 3 24+3n-15=24
•then u cancel equal terms 3n-15=0
•Move the constant to the right
3n-15=0
3n=15
•Divide both sides by 3
Answer is n=5 ☺️

8 0
4 years ago
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