Help geometry what I m jlf Picture provided
1 answer:
Answer:
which agrees with option"B" of the possible answers listed
Step-by-step explanation:
Notice that in order to solve this problem (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from , since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as
and
. (see attached image)
We put our efforts into solving the right angle triangle denoted with green borders.
Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by :
Therefore, the two equal acute angles in the triangle JOH should add to:
resulting then in each small acute angle of measure
.
Now referring to the green sided right angle triangle we can find find angle JLG, using:
Finally, the requested measure of angle JLF is obtained via:
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The polynomial with 6 roots is the one of degree 6, so the correct option is:
<h3>Which polynomial function has 6 roots?</h3>
You need to remember that if p(x) is a polynomial of degree N, then it has N roots (such that some of these N roots may be equal or not).
Then we just need to find the polynomial of degree 6. (Remember that the degree represents the maximum exponent of the polynomial).
In this case, the only one of degree 6 is:
Which is the last option.
If you want to learn more about polynomials, you can read:
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