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3 years ago

1/2 ху if x = 8, y = 3

Mathematics

2 answers:

Sergeu [11.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

We just plug in 8 for x and 3 for y which gives us 1/2 * 8 * 3 = 12.

Juliette [100K]3 years ago

4 0

Answer:

Step-by-step explanation:

1/2(8)(3)

4(3)

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Step-by-step explanation:

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h(0)= -16(0)^2-8(0)+120

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3 years ago

Will mark brainliest!! solve & simplify the following equation: 2x²-7x=4

Goryan [66]

Answer:

x= −1 /2 or x=4

Step-by-step explanation:

This is ALGEBRA, equations, factoring and zero property. ok.. let's solve this step-by-step

2x^2−7x=4

Step 1: Subtract 4 from both sides.

2x^2−7x−4 =4 −4

2x^2−7x−4=0

Step 2: Factor left side of equation.

(2x+1)(x−4)=0

Step 3: Set factors equal to 0.

2x+1=0 or x−4=0

x= −1 /2 or x=4

(BTW, there are supposed to be two answers, it's factoring)

Sorry if the format is not clear, but I hope this helped (really feel you, algebra can be brain-striking)!! Please leave a comment, rating and/or mark as the brainliest-whichever you think I deserve! Thank You :)

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3 years ago

A rectangle has width that is 6 meters less than the length. The area of the rectangle is 280 square meters. Find the dimensions

salantis [7]

Dimensions are length 20 meter and width 14 meter

Solution:

Let "a" be the length of rectangle

Let "b" be the width of rectangle

Given that,

A rectangle has width that is 6 meters less than the length

Width = length - 6

b = a - 6

The area of the rectangle is 280 square meters

The area of the rectangle is given by formula:

$Area = length \times width$

Substituting the values we get,

$Area = a \times (a-6)\\\\280 = a^2-6a\\\\a^2-6a -280=0$

Solve the above equation by quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\\quad x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-6,\:c=-280:\quad a_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:1\left(-280\right)}}{2\cdot \:1}$

$a =\frac{6 \pm \sqrt{36+1120}}{2}\\\\a = \frac{6 \pm \sqrt{1156}}{2}\\\\a = \frac{6 \pm 34}{2}\\\\Thus\ we\ have\ two\ solutions\\\\a = \frac{6+34}{2} \text{ or } a = \frac{6-34}{2}\\\\a = 20 \text{ or } a = -14$

Since, length cannot be negative, ignore a = -14

Thus solution of length is a = 20

Therefore,

width = length - 6

width = 20 - 6 = 14

Thus dimensions are length 20 meter and width 14 meter

6 0

3 years ago

1/2 ху if x = 8, y = 3​

1/2 ху if x = 8, y = 3