Circumfrence: pi times diameter
7.9*
circumfrence is approximatley 24.806
area:
a=
*(1/2(d))^2
a= 48.99
Answer:
1/5^9
Step-by-step explanation:
You keep the 5 the same
Then you subtract the exponents...
-6 - 3 = -9
Since it’s negative and you can’t have a negative exponent you have to put a 1 as the numerator. So...
1/5^9
This is a problem you need to solve using logs. When you use logs you can "pull" the exponents down in front of the log to get a new equation that looks like this: 2x^3 + x^2 log 81 = 6x - 3 log 27. Now divide both sides by log 81 and 6x - 3 simultaneously to get (2x^3 + x^2)/(6x - 3) = (log 27)/(log 81). If you do the log math on the right side you get .75. Now multiply both sides by 6x-3 to get 2x^3+x^2 = .75(6x-3). If you distribute that out on the left side you'll get 2x^3+x^2=4.5x-2.25. Now move everything over to the left side and set the whole thing equal to 0: 2x^3+x^2-4.5x+2.25=0. When you solve for x, you are in essence factoring, so do this by grouping: x^2(2x+1)-2.25(2x+1). Now finally factor out the 2x+1 to get (2x+1)(x^2-2.25). You're not done yet though cuz you need to solve each of those for x: 2x+1=0, and x= -1/2; x^2=2.25, and x=+/- 1.5. So all the values for x here are -1/2, 1.5, and -1.5
It is not A,B, or D.
so it has to be C. wish I knew this when taking test.
let me know if it was right. I hope this is somewhat helpful.
Well the question doesnt show any number for a side or anything but we can solve this with algebra if we say that a side from one base to next has a length of x. so we know each side has length x and that the shape they make is square. This means we are only searching for the diagonal of a square.
remember that a diagonal forms and isoscoles right triangle with the 2 sides being equal and the diagonal as the hypotenuse. Using the pythagoream theorem we can say that
a^2 + b^2 = c^2
we said all side lengths are x so we can put x in for a and b and get
x^2 + x^2 = c^2
2x^2 = c^2
c = x * squareroot(2)
that is the basic fundamental answer that will always work when working with diagonals of squares.
so if the length between bases is 90 ft, we could plug this in and get
c = 90 ft * squareroot(2)
c = 127.28 ft
