Answer:
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Let
Vco------------------- >Volume cone
Vcy------------------ >Volume cylinder
r= 8mm
hco----------- > height of cone=18 mm
hcy------------ > height of cylinder =54-18=36 mm
then
Vco=π*r² *hco/3--------- > π*8² *18/3=π*384 mm³
Vcy=π*r² *hcy--------- > π*8² *36=π*2304 mm³
the total cubic millimeters of sand=Vco+Vcy=π*384+π*2304=π*2688
if 10π cubic millimeters --------------------- > 1 seg
π*2688--------------------------------- X
X=π*2688/10π=268.8 seg
the answer is 268.8 seg
Answer:
14.308-665544906576543214990
Answer: The answer is 2,713 in³
The volume (V) of the prop is the sum of the volume of cone (V1) and half of the volume of the sphere (V2): V = V1 + 1/2 * V2
Volume of the cone is:
V1 = π r² h / 3
According to the image,
h = 14 in
r = 9 in
and
π = 3.14
V1 = 3.14 * 9² * 14 / 3 = 1,186.92 in³
The volume of the sphere is:
V2 = π r³ * 4/3
According to the image,
r = 9 in
and
π = 3.14
V2 = 3.14 * 9³ * 4/3 = 3,052.08 in³
The volume of the prop is:
V = V1 + 1/2 * V2
V = 1,186.92 in³ + 1/2 * 3,052.08 in³
V = 1,186.92 in³ + 1,526.04 in³
V = 2,712.96 in³ ≈ 2,713 in³
It would be the first graph
That is because the 2nd and 3rd graphs start at a point close to (0,-2) but it is not the correct point.
Now using (0,0) as a solution plug it in for the x and y values like so
0 <−3(0)−2 = 0 < -2
0 ≤ 0 −2 = 0 ≤ -2
This does not work so solutions from (0,0) up cannot be solutions, so the first graph must be the right answer.
