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DochEvi [55]
3 years ago
7

Click ___ to move a stacked object to the top of the stack.

Computers and Technology
1 answer:
laila [671]3 years ago
4 0
Click interfering to move a stacked object to the top of the stack
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Choose the types of education an ISS professional
Viefleur [7K]

Answer:

It's A. a CompTIA certificate and D. a Microsoft-certified desktop support

certificate

Explanation:

I got it right.

7 0
4 years ago
When a security professional is presented with a contract drawn up by a company's legal department, which allows them to "hack"
kumpel [21]

<em>The answer is : He must consult with a lawyer. </em>

<em>Hacking is considered illegal and in other countries, it is punishable by law. Hacking is gaining unauthorized access to a network. Even when someone is giving you permission to do it, it is still wrong and illegal. Therefore, you must know of your rights and make all the party involved to signed an agreement to save yourself.</em>

8 0
3 years ago
Write a recursive function called digit_count() that takes a positive integer as a parameter and returns the number of digits in
Gelneren [198K]

Using the computational knowledge in python it is possible to write a code that Write a recursive function called digit_count()

<h3>What is a function in Python?</h3>

In Python, a function is a sequence of commands that performs some task and that has a name. Its main purpose is to help us organize programs into chunks that correspond to how we envision a solution to the problem.

<h3>Writting the code in python:</h3>

<em>def countDigits(n):</em>

<em>   if n< 10:</em>

<em>      return 1</em>

<em>   else:</em>

<em>       return 1 + countDigits(n / 10)</em>

See more about python at brainly.com/question/13437928

#SPJ1

8 0
2 years ago
Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria
butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

       if side1 == side2 == side3:

           print("Equilateral Triangle")

       elif side1 == side2 or side1 == side3 or side2 == side3:

           print("Isosceles Triangle")

       else:

           print("Scalene Triangle")

   else:

       print("Invalid Triangle")

else:

   print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

<em>side1 = float(input("Side 1: ")) </em>

<em>side2 = float(input("Side 2: ")) </em>

<em>side3 = float(input("Side 3: ")) </em>

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

   if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

<em>        if side1 == side2 == side3: </em>

<em>            print("Equilateral Triangle") </em>

Check if the triangle is isosceles

<em>        elif side1 == side2 or side1 == side3 or side2 == side3: </em>

<em>            print("Isosceles Triangle") </em>

Otherwise, it is scalene

<em>        else: </em>

<em>            print("Scalene Triangle") </em>

Print invalid, if the sides do not make a valid triangle

<em>    else: </em>

<em>        print("Invalid Triangle") </em>

Print invalid, if the any of the sides are negative

<em>else: </em>

<em>    print("Invalid Triangle")</em>

4 0
3 years ago
Which of these is the most likely result if the internet download speed in your home is 25 Mbps?
sashaice [31]

Answer:

Streaming movies may stop to buffer

Explanation:

microphones have a set record limit, and games downloaded wont generate errors unless something in the code is wrong, printers don't really need to connect to internet to work except for some, and streaming movies buffer because as you are watching them it downloads the next few minutes.

3 0
3 years ago
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