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DochEvi [55]
3 years ago
7

Click ___ to move a stacked object to the top of the stack.

Computers and Technology
1 answer:
laila [671]3 years ago
4 0
Click interfering to move a stacked object to the top of the stack
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Hi there! I am writing a code to make a square using a drone, however I’m having trouble doing so. The website that I’m writing
Jlenok [28]

Answer:

i might

Explanation:

3 0
2 years ago
PLEASE HELP PROGRAMMING WILL GIVE BRAINLIEST
DaniilM [7]

Answer:

1. would be B.

2. would be D

3. May I ask if it can be multiple answers?

Explanation:

1. In coding a if statement has to follow if something is true or not. If we are talking about a if and then statement it will skip that block and move to the next block of the "then" part of the "if then" Statement if the first part is reported false

2. This is a easy one, so it has to be either a 3.25 GPA or higher or they have to have either 100 hours or more.

3. waiting for a comment back :)

4 0
4 years ago
Considering the following algorithm, which of the following requirements are satisfied?
Alisiya [41]

Answer:

b) Bounded Waiting

Explanation:

int currentThread = 1;

bool thread1Access = true;

bool thread2Access = true;

thread1 { thread2 {

While (true) {

                   While (true)

                                   {

                     while(thread2Access == true)

                                       {

                                      while(thread1Access == true)

                                       {

                                            If (currentThread == 2) {

                                              If (currentThread == 1)

                                                {        

                                                  thread1Access = false; thread2Access = false;

                                                  While (currentThread == 2);

                                                 While (currentThread == 1);

                                                  thread1Access = true; thread2Access = true;

} }

/* start of critical section */ /* start of critical section */

currentThread = 2 currentThread = 1

… ...

/* end of critical section */ /* end of critical section */

thread1Access = false; thread2Access = false;

… ...

} }

} }

} }

It can be seen that in all the instances, both threads are programmed to share same resource at the same time, and hence this is the bounded waiting. For Mutual exclusion, two threads cannot share one resource at one time. They must share simultaneously. Also there should be no deadlock. For Progress each thread should have exclusive access to all the resources. Thus its definitely the not the Progress. And hence its Bounded waiting.

4 0
4 years ago
Access-lists pose a logical problem which often has more than one solution. Can you think of a different set of rules or placeme
Maksim231197 [3]

Answer:

Question is incomplete. it needs a topology diagram and also it needs Router R1 table. I assume User has access to the topology and Routing table.

Below Configuration will help to fix ACL problem

Hosts from the 172.16.0.0/16 network should have full access to Server1, Server2 and Server3 but this is not currently the case, as L1 can’t communicate to Server2 or Server3.

Explanation:

Following Configuration on Cisco Router R1 will help to fix all the ACL problems.

enable

configure terminal

no ip access-list standard FROM_10

ip access-list standard FROM_10

deny host 10.0.0.2

permit any

exit

!

no ip access-list standard FROM_172

ip access-list standard FROM_172

permit host 172.16.0.2

exit

!

interface GigabitEthernet0/0

ip access-group FROM_192 out

end

write memory

!

7 0
3 years ago
In the United States there are more women than men, but women are referred to as a minority group? Why are they considered a min
ziro4ka [17]
Cause they make up half the population of the united states of america
7 0
3 years ago
Read 2 more answers
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