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saul85 [17]
3 years ago
15

A user is attempting to format a 4 TB HDD using NTFS but only has the option to format the disk with a size of approximately 2 T

B.
What is the most likely reason the user is unable to format the disk to its full capacity?
a. The disk is using the MBR partitioning scheme.
b. The disk is using the GUID partitioning scheme.
c. NTFS only supports up to 2.2 TB volume sizes.
d. The user chose a primary partition instead of extended partition.
Computers and Technology
1 answer:
matrenka [14]3 years ago
4 0

Answer:

The correct option is option A.

Explanation:

The MBR ( master boot record) partitioning scheme maximum partition size is 2 TB.

This limit occurs because the locations were the partitions are stored, can be of a maximum of 4 bytes long, and because the disk works in hexadecimal, the max value it can store is all F's. Thus, we have that the maximum partition sector would be 4,294,967,295, and since each sector is limited to 512 bytes, this result in the partition being limited to only 2 TB.

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The  statements that correctly describe the time complexity of data structures with N data are:

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<h3>What is time complexity of data structures?</h3>

Time Complexity of an algorithm is known to be the depiction of the amount of time needed by the algorithm to carry out to completion.

Note that The  statements that correctly describe the time complexity of data structures with N data are:

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The objective fuction of linear progrmming should be
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D. Wide angle

Explanation:

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David bought 5.2 pounds of oranges for $1.20 per pound . how much did david spend ..............................................
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Write the definition of a method, isReverse, whose two parameters are arrays of integers of equal size. The method returns true
Marat540 [252]

Answer:

   public static boolean isReverse(int [ ]a, int [ ]b ){

       for (int i=0;i<a.length;i++)

       {

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Explanation:

Using a for loop, we go through the elements of the first array. The if comapres and checks if any of the values are not the same as the appropriate value on the other array, if it is so, then it is not a reverse, and we return false. else  we return true.

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