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saul85 [17]
3 years ago
15

A user is attempting to format a 4 TB HDD using NTFS but only has the option to format the disk with a size of approximately 2 T

B.
What is the most likely reason the user is unable to format the disk to its full capacity?
a. The disk is using the MBR partitioning scheme.
b. The disk is using the GUID partitioning scheme.
c. NTFS only supports up to 2.2 TB volume sizes.
d. The user chose a primary partition instead of extended partition.
Computers and Technology
1 answer:
matrenka [14]3 years ago
4 0

Answer:

The correct option is option A.

Explanation:

The MBR ( master boot record) partitioning scheme maximum partition size is 2 TB.

This limit occurs because the locations were the partitions are stored, can be of a maximum of 4 bytes long, and because the disk works in hexadecimal, the max value it can store is all F's. Thus, we have that the maximum partition sector would be 4,294,967,295, and since each sector is limited to 512 bytes, this result in the partition being limited to only 2 TB.

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natali 33 [55]
No. The computer dose not understand what you are attempting to do, therefore it will not understand how to check for logic errors. The compiler will only check for syntax errors.
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You want to get information about DNS request types and DNS query packet content. What kind of DNS logging do you need to enable
ololo11 [35]

Answer:

Option C i.e., Analytic event logging is the correct answer.

Explanation:

The user required to enable Analytic event logging Type of DNS logging to take data or information related to the type of DNS request and also the content packet of the DNS query. By Analytic event logging, Users get data about the forms of DNS requests and the size of the DNS query packets. That's why the following option is correct.

8 0
3 years ago
def getCharacterForward(char, key): """ Given a character char, and an integer key, the function shifts char forward `key` steps
zhenek [66]

Answer:

  1. def getCharacterForward(char, key):  
  2.    charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
  3.    if(len(char) > 1):
  4.        return None  
  5.    elif(not isinstance(key, int)):
  6.        return -1
  7.    else:
  8.        index = charList.find(char)
  9.        if(index + key <= 25):
  10.            return charList[index + key]
  11.        else:
  12.            return charList[(index + key)% 26]
  13. print(getCharacterForward("C", 4))
  14. print(getCharacterForward("X", 4))

Explanation:

Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.

Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).

Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).

However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).  

We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:

G

B

8 0
3 years ago
I need this answer right away!
Degger [83]

Answer:

Foundation.

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Ionic.

HTML KickStart.

Semantic UI

Explanation:

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Translate the following pseudocode for randomly permuting the characters in a string into a C++ program.
Svetllana [295]

Answer:

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Explanation:

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