Take the variable to be x
4x^3-7
Answer:
The conjecture is that the unit digit of 4^n = 4 when n = odd also 4^n = 6 when n = even
Step-by-step explanation:
The conjecture is that the unit digit of 4^n = 4 when n = odd also 4^n = 6 when n = even
To prove this conjecture
unit digit = 6
hence the property is true for ; n = 1 and n = 2 and also for every odd and even number ( i.e. from 1 to 8 )
Step-by-step explanation:
ar of quadilateral
=16×7×7×20
=12080cmsq
So it tells us that g(3) = -5 and g'(x) = x^2 + 7.
So g(3) = -5 is the point (3, -5)
Using linear approximation
g(2.99) is the point (2.99, g(3) + g'(3)*(2.99-3))
now we just need to simplify that
(2.99, -5 + (16)*(-.01)) which is (2.99, -5 + -.16) which is (2.99, -5.16)
So g(2.99) = -5.16
Doing the same thing for the other g(3.01)
(3.01, g(3) + g'(3)*(3.01-3))
(3.01, -5 + 16*.01) which is (3.01, -4.84)
So g(3.01) = -4.84
So we have our linear approximation for the two.
If you wanted to, you could check your answer by finding g(x). Since you know g'(x), take the antiderivative and we will get
g(x) = 1/3x^3 + 7x + C
Since we know g(3) = -5, we can use that to solve for C
1/3(3)^3 + 7(3) + C = -5 and we find that C = -35
so that means g(x) = (x^3)/3 + 7x - 35
So just to check our linear approximations use that to find g(2.99) and g(3.01)
g(2.99) = -5.1597
g(3.01) = -4.8397
So as you can see, using the linear approximation we got our answers as
g(2.99) = -5.16
g(3.01) = -4.84
which are both really close to the actual answer. Not a bad method if you ever need to use it.
Answer:
4√2 and 5+4√2
Step-by-step explanation:
Let the two numbers be x ad y
Smaller = y
Bigger = x
If a positive real number is 5 more than another, then;
x = 5 + y ... 1
When - 10 times the smaller is added to the square of the larger, the result is 57, then;
-10y + x² = 57 ...2
Substitute 1 into 2;
-10y + (5+y)² = 57
-10y + 25+10y+y² = 57
y²+25 = 57
y² = 57 - 25
y² = 32
y = √32
y = 4√2
Since x = 5 + y
x = 5 + 4√2
Hence rhe numbers are 4√2 and 5+4√2
