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IrinaK [193]
3 years ago
5

Given cos alpha=15/17 in Q1, find cos(alpha/2) And sin(alpha/2)​

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

• cos(α/2) = (4/17)√17

• sin(α/2) = (√17)/17

Step-by-step explanation:

The appropriate hαlf-angle identities are:

sin(α/2) = √((1 -cos(α))/2)

cos(α/2) = √((1 +cos(α))/2)

Putting in your given values for cos(α), we have ...

cos(α/2) = √((1 +15/17)/2) = √(16/17) = 4(√17)/17

sin(α/2) = √((1 -15/17)/2) = √(1/17) = (√17)/17

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The hypotenuse is always directly across from the right angle.

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<u><em>Therefore, the side with the hypotenuse is side 3</em></u>, because we can see that the angle between side 1 and side 2 is the right angle, and the hypotenuse would be directly across.

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