(10 + 9) x (3 - 1) x 2 = +75
19 x 2 x 2
76
76 > 75
L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
Answer:
x= 6 and b= 126°
Step-by-step explanation:
okay the first step to solving this is understanding what are the properties of ∠A and ∠B.
so the angles are equal to each other because they are alternate interior angles.
if that is settled it means the equation for both angles would be equal to each other as well.
∠A= 8x + 78° ∠B= 2x + 114°
therefore: 8x + 78= 2x + 114
then solve for x:
- isolate x and the answer is equal to 6 at the end
now you are looking for angle b, so you input x which is 6 into the equation;
= 2(6) + 114°
=12 + 114°
=126°
<span>For example
let there be 100 students
so the number of girls=40
20% of girls=20%of40=20*40/100=8 wear glasses
Which means 8 out of 100 students wear glasses
So 8%students wear glasses</span>
