All categories

3 years ago

Solve the formula A= 8/2 for r.

Mathematics

2 answers:

inna [77]3 years ago

8 0

Answer:

The steps are :

$A = \pi {r}^{2}$

$\frac{A}{\pi} = {r}^{2}$

$r = \sqrt{ \frac{A}{\pi} }$

Therefore, the answer is B.

KATRIN_1 [288]3 years ago

8 0

Answer: the answer is B.

You might be interested in

Please help asap Find the measure of angle y. Round your answer to the nearest hundredth. (please type the numerical answer only

mario62 [17]

Answer:

in degree 11.54

in radians 0.20

Step-by-step explanation:

soh= o/h

sin(y)=4/20

y=sin^-1(4/20)

8 0

3 years ago

Read 2 more answers

What is the eighth term of the arithmetic sequence? An=<br> 10n – 14?

Alja [10]

Answer:

A8 = 66 [8th term]

Step-by-step explanation:

Given the explicit arithmetic sequence An = -14 + 10n → -4 + 10(n-1)

To find the 8th term. An nth term is where n is n in the sequence. So substitute 8 for n, and simplify.

So A8 = -4 + 10(8-1) → -4 + 10(7) → -4 + 70 → 70 - 4 → 66.

3 0

3 years ago

A plumber charges an initial amount,x, to make a house call plus an hourly rate,y, for the time he is working.A 1-hour job costs

Inessa05 [86]

X=$30
y=$60

1 hour job- 60x1=60+30=90
3 hour job-60x3=180+30=210

5 0

3 years ago

Need help real fast please help really need it

Vladimir79 [104]

Answer:

burrito price=$8

Taco Price=$6

Step-by-step explanation:

x=burrito price

y=taco price

3x+4y=48

solve for y

y= −3 /4 x+12

plug in

6x+2y=60

6x+2( −3 /4 x+12)=60

x=8

now plug in for x

3x+4y=48

3(8)+4y=48

y=6

x=8

burrito price=$8

Taco Price=$6

8 0

3 years ago

Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1

natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r=\sqrt{(-5-(-2))^2+(3-1)^2}$

$r=\sqrt{(-5+2)^2+(2)^2}$

$r=\sqrt{(-3)^2+(2)^2}$

On further simplification, we get

$r=\sqrt{9+4}$

$r=\sqrt{13}$

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and $r=\sqrt{13}$ .

$(x-(-2))^2+(y-1)^2=(\sqrt{13})^2$

$(x+2)^2+(y-1)^2=13$

Therefore, the equation of the circle is $(x+2)^2+(y-1)^2=13$ .

8 0

3 years ago