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Viefleur [7K]
3 years ago
11

Which choices are in the solution set of the equation below? Check all that

Mathematics
2 answers:
aivan3 [116]3 years ago
7 0
F and D are the most reasonable choices!
Marysya12 [62]3 years ago
5 0
I believe the answer to this is F and i think D also
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Hi, I have utterly no idea what I'm doing here.
Anna11 [10]

Answer:

Factored form: 2x(2x^2+x+1)

Step-by-step explanation:

You're subtracting them. :)

6 0
2 years ago
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Solve the equation for w. x=w/a
Allisa [31]

Answer:

<h3>w=xa</h3>

Step-by-step explanation:

Rewrite the equation as w/a=x

w/a=x

Multiply both sides of the equation by a

w=x*(a)

Multiply x by a

w=xa

<em>Hope this helped!</em>

5 0
2 years ago
Choose the expression that represents a linear expression.
tresset_1 [31]

Answer:

Step-by-step explanation:

A linear expression has the highest power of the variable to 1, i.e ax+b

Then only the first option is in a linear expression format

9x-2

6 0
3 years ago
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Classify this triangle.
scoundrel [369]

Did you know not only people have to respond your question but you can also search it on the internet and find atleast a hint?

6 0
2 years ago
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Solve for a side in right triangles
Ket [755]

Answer:

2.33

Step-by-step explanation:

imagine a circle. its center is A, and it goes through B, so its radius is AB.

then it is important to know that the sum of all the angles in a triangle is 180 degrees.

one angle (at C) is 90. the angle at B is 25. so, the angle at A is 180 - 90 - 25 = 65 degrees.

more back to our circle.

in this circle the line CB is the sine of the angle at A multiplied by the radius.

and AC is the cosine of the angle at A multiplied by the radius.

we can ignore the orientation + and - of these functions, as we are only interested in the absolute length (and we can mirror the triangle, and all the angles and side lengths still stay the same).

=> CB = sin(A)×AB

AC = cos(A)×AB

=> 5 = sin(65)×AB

=> AB = 5 / sin(65)

=> AC = cos(65)×5/sin(65) = 5 × (cos(65)/sin(65)) =

= 5 × cot(65) = 2.33

3 0
2 years ago
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