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3 years ago

5) What expression represents the square of the binomial (-9 + 2i) in simplest form?

Mathematics

1 answer:

Lerok [7]3 years ago

7 0

Answer:

Step-by-step explanation:

that is the simplest form.

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Please help it is math

olasank [31]

Answer:

A linear function has the form y=mx+b

A line has a proportional relationship if y/x is always the same ratio for any value.

The slope m=(y2-y1)/(x2-x1) for some two points on a line is always constant, else it wouldn't create a line.

A line won't be proportional if you adapt b because the ratio of y/x won't match the slope anymore.

In the end this means all lines with proportional relationships must intersect (0,0) or in other words f(0)=0.

This happens if they have the shape y=mx.

Step-by-step explanation:

hope this helps pls mark me brainliest

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2 years ago

Max can type 160 words in 5 minutes. How long would it take him to type 400 words? * A. 12.50 minB. 13 minC. 10.50 minD. 12 min

blagie [28]

To find how long it would take him, one has to divide 400 by 160 and then multiply 5 by what that number is. You multiply 5 by the quotient because that is the number that would make it proportional. 400/160 x 5 is 12.5, meaning that the answer is 12.5 minutes, or A.

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3 years ago

PLEASEEE HELP THANK YOU!

Fittoniya [83]

Answer:

Hi Sophia! The answer is the option 3!

Step-by-step explanation:

Check the picture!

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3 years ago

Which is a true statement about angles 1 and 2? O the two angles are supplementary

lana66690 [7]

C neither
Thank you hope this helps

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2 years ago

Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65

erma4kov [3.2K]

Answer:

Probability that the sample average is at most 3.00 = 0.98030

Probability that the sample average is between 2.65 and 3.00 = 0.4803

Step-by-step explanation:

We are given that the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65 and standard deviation 0.85.

Also, a random sample of 25 specimens is selected.

Let X bar = Sample average sediment density

The z score probability distribution for sample average is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = 2.65

$\sigma$ = standard deviation = 0.85

n = sample size = 25

(a) Probability that the sample average sediment density is at most 3.00 is given by = P( X bar <= 3.00)

P(X bar <= 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 2.06) = 0.98030

(b) Probability that sample average sediment density is between 2.65 and 3.00 is given by = P(2.65 < X bar < 3.00) = P(X bar < 3) - P(X bar <= 2.65)

P(X bar < 3) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{3-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z < 2.06) = 0.98030

P(X bar <= 2.65) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ <= $\frac{2.65-2.65}{\frac{0.85}{\sqrt{25} } }$ ) = P(Z <= 0) = 0.5

Therefore, P(2.65 < X bar < 3) = 0.98030 - 0.5 = 0.4803 .

8 0

3 years ago