Question

PLEASE HELP ASAP!!!!

Answer 1

Answer:

j(x) is an odd function

Step-by-step explanation:

We are given;

j(x) = 220/x³ and j(-x) = 220/(-x)³

Now,

when x = 1;

j(x) = 220/1³ = 220/1 = 220

j(-x) = 220/(-1)³ = 220/-1 = -220

When x = 2;

j(2) = 220/2³ = 220/8

j(-2) = 220/(-2)³ = -220/8

Now, Algebraically, function j would be even if and only if j(-x) = j(x) for all x in the domain of j. While j is odd if and only if j(-x) = -j(x) for all x in the domain of j.

From the values gotten, we can see that :j(-x) = -j(x). Thus, we can say that j(x) is an odd function.

Answer 2

Answer:

A) j(x) is an odd function.

Step-by-step explanation: