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Bingel [31]
2 years ago
9

What is 1/2 of simplified in fraction form

Mathematics
1 answer:
Leokris [45]2 years ago
8 0

Answer:

it already is in its simple form.

Converted to a decimal:

0.5 (rounded to 6 decimal places)

GCD:

1

Hopefully I helped answer your question.

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Put 18/45 in simplest form
Nesterboy [21]
Okay so 18/45 = 2/5 in simplest form. hope this helped
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Nelson got a pack of 12 pencils. he took 3 pencils and put it in is desk at school and 2 pencils to put in is locker at school.
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8 0
2 years ago
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
Renna pushed the button for the elevator to go up, but it would not move. The weight limit for the elevator is 450 kilograms, bu
alina1380 [7]
Here is the solution based on the given situation above.
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So to get the answer, first we need to deduct 450kg from 750 kgs to get the excess weight. So 750 - 450 is 300kgs. Next, we divide 300 by 70kgs to get the number of passengers that need to get off so 300/70 is 4.3. Therefore, there should be 4 passengers who weigh 70 kilograms that need to get off the elevator. 
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Mice21 [21]

Answer:

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  • B. -1
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Step-by-step explanation:

The domain includes all x values, and here, it is [-2, 4].

6 0
2 years ago
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