Answer:
Given:
The distances, in yards, that a team moves on its first five plays are 2, 21, 4, 3, and 25.
Solved:
1. The greatest number is 25
2. If the moved distances are square, which one is largest?
3. The move which is greater than 4 is considered "big play"
=> 21 and 25 are big play (21 > 4, 25 > 4)
Hope this helps!
:)
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
Answer:
15 liters
Step-by-step explanation:
Given:
We need 5 liters of Yoda soda for 12 guest.
To find:
If we have 36 guest how many liters of Yoda soda we need.
Solution:
<u>By unitary method:</u>
For 12 guests, we need liters of Yoda soda = 5
For 1 guest, we need liters of Yoda soda = 
For 36 guests, we need liters of Yoda soda = 
Therefore, we need 15 liters of Yoda soda for 36 guests.
