Answer:

Step-by-step explanation:
Given (Missing Information):
;
; 
Required
Determine the volume
Using Shell Method:

First solve for a and b.
and
Substitute 8 for y

Take 2/3 root of both sides





This implies that:

For 
This implies that:

So, we have:


The volume of the solid becomes:

Open bracket



Integrate
![V = 2\pi * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B%5Cfrac%7B8x%5E2%7D%7B2%7D%20-%20%5Cfrac%7Bx%5E%7B1%2B%5Cfrac%7B5%7D%7B2%7D%7D%7D%7B1%2B%5Cfrac%7B5%7D%7B2%7D%7D%5D%5Cvert%5E4_0)
![V = 2\pi * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B4x%5E2%20-%20%5Cfrac%7Bx%5E%7B%5Cfrac%7B2%2B5%7D%7B2%7D%7D%7D%7B%5Cfrac%7B2%2B5%7D%7B2%7D%7D%5D%5Cvert%5E4_0)
![V = 2\pi * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B4x%5E2%20-%20%5Cfrac%7Bx%5E%7B%5Cfrac%7B7%7D%7B2%7D%7D%7D%7B%5Cfrac%7B7%7D%7B2%7D%7D%5D%5Cvert%5E4_0)
![V = 2\pi * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B4x%5E2%20-%20%5Cfrac%7B2%7D%7B7%7Dx%5E%7B%5Cfrac%7B7%7D%7B2%7D%7D%5D%5Cvert%5E4_0)
Substitute 4 and 0 for x
![V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%28%5B%7B4%2A4%5E2%20-%20%5Cfrac%7B2%7D%7B7%7D%2A4%5E%7B%5Cfrac%7B7%7D%7B2%7D%7D%5D%20-%20%5B%7B4%2A0%5E2%20-%20%5Cfrac%7B2%7D%7B7%7D%2A0%5E%7B%5Cfrac%7B7%7D%7B2%7D%7D%5D%29)
![V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%28%5B%7B4%2A4%5E2%20-%20%5Cfrac%7B2%7D%7B7%7D%2A4%5E%7B%5Cfrac%7B7%7D%7B2%7D%7D%5D%20-%20%5B0%5D%29)
![V = 2\pi * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B4%2A4%5E2%20-%20%5Cfrac%7B2%7D%7B7%7D%2A4%5E%7B%5Cfrac%7B7%7D%7B2%7D%7D%5D)
![V = 2\pi * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B64%20-%20%5Cfrac%7B2%7D%7B7%7D%2A2%5E2%5E%7B%2A%5Cfrac%7B7%7D%7B2%7D%7D%5D)
![V = 2\pi * [{64 - \frac{2}{7}*2^7]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B64%20-%20%5Cfrac%7B2%7D%7B7%7D%2A2%5E7%5D)
![V = 2\pi * [{64 - \frac{2}{7}*128]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B64%20-%20%5Cfrac%7B2%7D%7B7%7D%2A128%5D)
![V = 2\pi * [{64 - \frac{2*128}{7}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B64%20-%20%5Cfrac%7B2%2A128%7D%7B7%7D%5D)
![V = 2\pi * [{64 - \frac{256}{7}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%7B64%20-%20%5Cfrac%7B256%7D%7B7%7D%5D)
Take LCM
![V = 2\pi * [\frac{64*7-256}{7}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%5Cfrac%7B64%2A7-256%7D%7B7%7D%5D)
![V = 2\pi * [\frac{448-256}{7}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%5Cfrac%7B448-256%7D%7B7%7D%5D)
![V = 2\pi * [\frac{192}{7}]](https://tex.z-dn.net/?f=V%20%3D%202%5Cpi%20%20%2A%20%5B%5Cfrac%7B192%7D%7B7%7D%5D)
![V = [\frac{2\pi * 192}{7}]](https://tex.z-dn.net/?f=V%20%3D%20%5B%5Cfrac%7B2%5Cpi%20%20%2A%20192%7D%7B7%7D%5D)


Hence, the required volume is:

Answer:
mean : add all of them and divide by how much they are
mode: is what repeats it self like 15 is the most repeated.
7 7/8= 63/8
3 1/4= 13/4
63/8 -13/4 we bring to the same denominator
(63-26)/8= 37/8
Answer:
116116
Step-by-step explanation:
Answer:
The process of calculating successive discounts of 8% and 10% on a $50 item is take 10% of $46.
Step-by-step explanation:
As given
successive discounts of 8% and 10% on a $50 item .
First find out for 8 % discount
8% is written in the decimal form
= 0.08
8 % of $50 item = 0.08 × 50
= $ 4
Price of item after 8% discount = 50 - 4
= $46
First find out for 10 % discount
10% is written in the decimal form
= 0.1
8 % of $48 item = 0.1× 46
= $4.6
Price of item after 8% discount = 46 - 4.6
= $41.4
Therefore in the successive discounts of 8% and 10% on a $50 item is $41.4 .