Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
54.7
Step-by-step explanation:
16.7 + 11 + 11 + 8 + 8 = 54.7
Note
I don't know how you are wrong but I showed my work and I got the same answer which is weird.
Answer:
5000
Step-by-step explanation:
50000 / 10= 5000
Answer: They are the same or equal to each other.
Step-by-step explanation:
Hope this helps.
