4 years ago

Find the equation of a parabola with vertex at the origin and focus (0, -32).

Mathematics

1 answer:

mrs_skeptik [129]4 years ago

4 0

Answer:

x^2 = -128y

Step-by-step explanation:

The general formula for this type of parabola is x^2 = 4ay where a is the y coordinate of the focus. So 4a = 4*-32 = 1-28.

So the answer is x^2 = -128y

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<img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20-%202ax%20%2B%20a%20%7B%7D%5E%7B2%7D%20%20-%20b%20%3D%200" id="TexFormu

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The answer is the last line.

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Use the quadratic formula

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=================

x = a +/- sqrt(a^2 - 4(1)*(a^2 - b)

========================

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=====================

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===================

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