Question

Help!!!!! I have no idea how to do this lol

Answer 1

Part 1) 
$y \ \textgreater \ 2-x \\ y \ \textgreater \ \frac{2}{3}x-2$

using a graph tool
see the attached figure N 1

the solution is the shaded area

Part 2) Chose a point
point (10,10)
x=10
y=10

for the inequality 1
y > 2-x----------> 10 > 2-10----------> 10 > -8------> is ok

for the inequality 2
y > (2/3)x-2------> 10 > (2/3)*10-2----> 10 > 6.67-2----> 10 > 4.67-----> is ok

Part 3) 
$y \leq -2x+3 \\ y \leq x-2$

using a graph tool
see the attached figure N 2

the solution is the shaded area

Part 4)Chose a point
point (-10,-20)
x=-10
y=-20

for the inequality 1
y <= -2x+3--------> -20 <= -2*(-10)+3----> -20 <= 23-----> is ok

for the inequality 2
y <= x-2------> -20 <=-10-2-----> -20 <= -12------> is ok